泰山220kV降压变电所电气部分设计
第二部分 计算书
第八章 主变的选择
P=68000+12000+4500+20000+10000=114500kw
Sm=ko(1+线损)P/ COSφ =0.95(1+5%)176500/0.85 =134369kVA
主变的额定容量为:
Se=0.75Sm=0.75*134369=107760kVA
总安装容量为215520kVA
根据上述计算数据,选择SFPZ7-120000/220型变压器作为本变电所的主变
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沈阳工程学院毕业设计
第九章 短路计算
9.1网络化简
系统等效网络如图1
图1
取sb?100MVA UB?UP
SB100?0.24*?0.381 SN63U%S13.5100X6?X7?X8?X9?X10?d*B?*?0.169
100SN10080S100X11?X12?X13?Xd*B?0.18*?0.18
SN100U%S13.6100X14?X15?X16?d*B?*?0.113
100SN100120S100X17?0.4*L*B?0.4*70*?0.053 2UB2302S100X18?0.4*L*B?0.4*60*?0.045 2UB2302S100X19?0.4*L*B?0.4*100*?0.076 22UB230S100X20?X21?0.4*L*B?0.4*56*?0.042 22UB230S100X23?X24?0.4*L*B?0.4*56*?0.042 2UB2302X1?X2?X3?X4?X5?Xd*
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泰山220kV降压变电所电气部分设计
X25?X26?Ud%SB14100*?*?0.125 100SN100120
以上网络可等效为图2:
图2
X27?X28?X29?X30?X31?X1?X6?0.381?0.169?0.550 X32?X33?X34?X11?X14?0.18?0.113?0.293
11X35?X20//X21?X20?*0.042?0.021
2211X36?X23//X24?X23?*0.042?0.021
2211X37?X25//X26?X25?*0.125?0.0625
22
以上网络可等效为图3:
图3
11X27?*0.550?0.110 5511X39?X32?*0.293?0.098
33X40?X22?X35?0.030?0.021?0.051 X38?以上网络可等效为图4:
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沈阳工程学院毕业设计
图4
X17*X180.053*0.045??0.014
X17?X18?X190.053?0.045?0.076X17*X190.053*0.076X42???0.023
X17?X18?X190.053?0.045?0.076X18*X190.045*0.076X43???0.020
X17?X18?X190.053?0.045?0.076以上网络可等效为图5: X41?4445423640220KV3760KV图5
X44?X38?X41?0.110?0.014?0.124 X45?X39?X43?0.098?0.020?0.118 以上网络可等效为图6:
图6
X44*X450.124?0.118?X42??0.023?0.083
X44?X450.124?0.118以上网络可等效为图7: X46?
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泰山220kV降压变电所电气部分设计
图7
X46*X400.051*0.083??0.032
X46?X400.051?0.083X0.032C1?47??0.39
X460.083X0.032C2?47??0.63
X400.051以上网络可等效为图8: X47?220KV48d13760KVd2图8
X48?X47?X36?0.032?0.021?0.053
9.2 短路电流的计算
为了选择220kV侧和60kV侧电气设备,在以上网络中选择了220kV母线和
(3)60kV母线两处短路d1(3) ,d2,其中60kV侧分别计算两台主变同时运行和只有一台
(3)(3)主变运行时发生三相短路的情况d2.1 ,d2.2。
(1)根据上图可求出220kV母线,既d1发生短路时系统的等效电抗为:
Xd1?X48?0.053 与变电所相连的两个发电厂到短路点的转移电抗为:
X0.053X转1?d1??0.136
C10.39系统到短路点的转移电抗为: X0.053X转2?d1??0.084
C20.63计算电抗标幺值为:
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