西工大C语言POJ习题答案 - 图文(3)

case 5:c=(a-40)*0.03+20*0.05+10*0.075+10*0.1;break; case 6: case 7: case 8:

case 9:c=(a-60)*0.015+20*0.03+20*0.05+10*0.075+10*0.1;break;

default:c=(a-100)*0.01+40*0.015+20*0.03+20*0.05+10*0.075+10*0.1; }

printf(\ return 0; } 7.

#include int main() {

double a,b,c; scanf(\ c=(int)a; if(a>c)a=c+1; if(a>15)

b=(a-15)*2.1+7+13*1.5; else { if(a>2)

b=(a-2)*1.5+7; else b=7; }

printf(\

return 0; } 8.

#include int main() {

int a,b,c,e,f=30,g=31,n;

scanf(\

if((a@0==0)||(a0!=0&&a%4==0)) e=29; else e=28; switch (b) {

case 1:n=c;break; case 2:n=g+c;break; case 3:n=g+e+c;break;

case 4:n=g+e+g+c;break; case 5:n=g+e+g+f+c;break; case 6:n=g+e+g+f+g+c;break; case 7:n=g+e+g+f+g+f+c;break; case 8:n=g+e+g+f+g+f+g+c;break; case 9:n=g+e+g+f+g+f+g+g+c;break; case 10:n=g+e+g+f+g+f+g+g+f+c;break; case 11:n=g+e+g+f+g+f+g+g+f+g+c;break; default: n=g+e+g+f+g+f+g+g+f+g+f+c; }

printf(\ return 0; } 9.