中铁十局集团有限公司 连镇铁路项目三分部临时用电专项施工方案
Kx = 0.70，Cosφ = 0.40，tgφ = 2.29 Pjs = Kx×Pe = 0.70× 5.50 = 3.85kW Qjs = Pjs×tgφ = 3.85× 2.29 = 8.82kVar (3)钢筋切断机
Kx = 0.70，Cosφ = 0.40，tgφ = 2.29 Pjs = Kx×Pe = 0.70× 7.00 = 4.90kW Qjs = Pjs×tgφ = 4.90× 2.29 = 11.23kVar (4)钢筋弯曲机
Kx = 0.70，Cosφ = 0.40，tgφ = 2.29 Pjs = Kx×Pe = 0.70× 3.00 = 2.10kW Qjs = Pjs×tgφ = 2.10× 2.29 = 4.81kVar (5)交流电焊机
Kx = 0.45，Cosφ = 0.45，tgφ = 1.98 将Jc = 40%统一换算到Jc = 100%的额定容量
Pe = n×(Jc/Jc1)1/2×Pn = 1×(0.40/1.00)1/2×17.37 = 10.99kW Pjs = Kx×Pe = 0.45× 10.99 = 4.94kW Qjs = Pjs×tgφ = 4.94× 1.98 = 9.81kVar (6)钢筋对焊机
Kx = 0.45，Cosφ = 0.40，tgφ = 2.29 Pjs = Kx×Pe = 0.45× 20.00 = 9.00kW Qjs = Pjs×tgφ = 9.00× 2.29 = 20.62kVar (7)钢筋调直切断机
Kx = 0.70，Cosφ = 0.40，tgφ = 2.29 Pjs = Kx×Pe = 0.70× 5.50 = 3.85kW Qjs = Pjs×tgφ = 3.85× 2.29 = 8.82kVar (8)钢筋弯曲机
Kx = 0.70，Cosφ = 0.40，tgφ = 2.29 Pjs = Kx×Pe = 0.70× 3.00 = 2.10kW Qjs = Pjs×tgφ = 2.10× 2.29 = 4.81kVar
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中铁十局集团有限公司 连镇铁路项目三分部临时用电专项施工方案
(9) 钢筋切断机
Kx = 0.70，Cosφ = 0.40，tgφ = 2.29 Pjs = Kx×Pe = 0.70× 7.00 = 4.90kW Qjs = Pjs×tgφ = 4.90× 2.29 = 11.23kVar (10)交流电焊机
Kx = 0.45，Cosφ = 0.45，tgφ = 1.98 将Jc = 40%统一换算到Jc = 100%的额定容量
Pe = n×(Jc/Jc1)1/2×Pn = 1×(0.40/1.00)1/2×17.37 = 10.99kW Pjs = Kx×Pe = 0.45× 10.99 = 4.94kW Qjs = Pjs×tgφ = 4.94× 1.98 = 9.81kVar (11)交流电焊机
Kx = 0.45，Cosφ = 0.45，tgφ = 1.98 将Jc = 40%统一换算到Jc = 100%的额定容量
Pe = n×(Jc/Jc1)1/2×Pn = 1×(0.40/1.00)1/2×17.37 = 10.99kW Pjs = Kx×Pe = 0.45× 10.99 = 4.94kW Qjs = Pjs×tgφ = 4.94× 1.98 = 9.81kVar (12)交流电焊机
Kx = 0.45，Cosφ = 0.45，tgφ = 1.98 将Jc = 40%统一换算到Jc = 100%的额定容量
Pe = n×(Jc/Jc1)1/2×Pn = 1×(0.40/1.00)1/2×17.37 = 10.99kW Pjs = Kx×Pe = 0.45× 10.99 = 4.94kW Qjs = Pjs×tgφ = 4.94× 1.98 = 9.81kVar (13)交流电焊机
Kx = 0.45，Cosφ = 0.45，tgφ = 1.98 将Jc = 40%统一换算到Jc = 100%的额定容量
Pe = n×(Jc/Jc1)1/2×Pn = 1×(0.40/1.00)1/2×17.37 = 10.99kW Pjs = Kx×Pe = 0.45× 10.99 = 4.94kW Qjs = Pjs×tgφ = 4.94× 1.98 = 9.81kVar (14)交流电焊机
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中铁十局集团有限公司 连镇铁路项目三分部临时用电专项施工方案
Kx = 0.45，Cosφ = 0.45，tgφ = 1.98 将Jc = 40%统一换算到Jc = 100%的额定容量
Pe = n×(Jc/Jc1)1/2×Pn = 1×(0.40/1.00)1/2×17.37 = 10.99kW Pjs = Kx×Pe = 0.45× 10.99 = 4.94kW Qjs = Pjs×tgφ = 4.94× 1.98 = 9.81kVar (15)钢筋室外加工照明
Kx = 1.00，Cosφ = 1.00，tgφ = 0 Pjs = Kx×Pe = 1.00× 96.00 = 96.00kW Qjs = Pjs×tgφ = 96.00× 0 = 0.00kVar (16)职工办公、生活区组
Kx = 1.00，Cosφ = 1.00，tgφ = 0 Pjs = Kx×Pe = 1.00× 50.00 = 50.00kW Qjs = Pjs×tgφ = 50.00× 0 = 0.00kVar (17)作业队办公、生活区组
Kx = 1.00，Cosφ = 1.00，tgφ = 0 Pjs = Kx×Pe = 1.00× 40.00 = 40.00kW Qjs = Pjs×tgφ = 40.00× 0 = 0.00kVar (18)总的计算负荷计算，干线同期系数取 Kx = 0.90 总的有功功率
Pjs=1.1×Kx×ΣPjs=1.1×0.90×(9.00+3.85+4.90+2.10+4.94+9.00+3.85+2.10+3.85+4.94+4.94+4.94+4.94+4.94+96.00+50.00+40.00) = 251.77kW
总的无功功率
Qjs=1.1×Kx×ΣQjs=1.1×0.90×(20.62+8.82+11.23+4.81+9.81+20.62+8.82+4.81+8.82+9.81+9.81+9.81+9.81+9.81+0.00+0.00+0.00) = 145.95kVar
总的视在功率
Sjs = (Pjs2+Qjs2)1/2 = (251.772+145.952)1/2 = 291.01kVA 总的计算电流计算
Ijs = Sjs/(1.732×Ue) = 291.01/(1.732×0.38) = 442.16A 7#变压器的负荷计算
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中铁十局集团有限公司 连镇铁路项目三分部临时用电专项施工方案
(1)混凝土搅拌楼
Kx = 0.70，Cosφ = 0.70，tgφ = 1.02 Pjs = Kx×Pe = 0.70× 250.00 = 175.00kW Qjs = Pjs×tgφ = 175.00× 1.02 = 178.54kVar (2)混凝土搅拌楼
Kx = 0.70，Cosφ = 0.70，tgφ = 1.02 Pjs = Kx×Pe = 0.70× 250.00 = 175.00kW Qjs = Pjs×tgφ = 175.00× 1.02 = 178.54kVar (3)职工办公、生活区
Kx = 1.00，Cosφ = 1.00，tgφ = 0 Pjs = Kx×Pe = 1.00× 50.00 = 50.00kW Qjs = Pjs×tgφ = 50.00× 0 = 0.00kVar (4)作业队办公、生活区
Kx = 1.00，Cosφ = 1.00，tgφ = 0 Pjs = Kx×Pe = 1.00× 40.00 = 40.00kW Qjs = Pjs×tgφ = 40.00× 0 = 0.00kVar (5)总的计算负荷计算，干线同期系数取 Kx = 0.90 总的有功功率
Pjs = 1.1×Kx×ΣPjs = 1.1×0.90×(175.00+175.00+50.00+40.00) = 435.60kW 总的无功功率
Qjs =1.1×Kx×ΣQjs = 1.1×0.90×(178.54+178.54+0.00+0.00) = 353.50kVar 总的视在功率
Sjs = (Pjs2+Qjs2)1/2 = (435.602+353.502)1/2 = 560.99kVA 总的计算电流计算
Ijs = Sjs/(1.732×Ue) = 560.99/(1.732×0.38) = 852.36A
五、选择变压器
1#变压器
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中铁十局集团有限公司 连镇铁路项目三分部临时用电专项施工方案
根据计算的总的视在功率选择S9-400/10 型三相电力变压器，它的容量为400.00kVA≥319.45kVA×1.20(增容系数)能够满足使用要求，其高压侧电压为10.00kV同施工现场外的高压架空线路的电压级别一致。
3#变压器
根据计算的总的视在功率选择S9-400/10 型三相电力变压器，它的容量为400.00kVA≥291.01kVA×1.20(增容系数)能够满足使用要求，其高压侧电压为10.00kV同施工现场外的高压架空线路的电压级别一致。
7#变压器
根据计算的总的视在功率选择S9-800/10 型三相电力变压器，它的容量为800kVA≥560.99kVA×1.20(增容系数)能够满足使用要求，其高压侧电压为10.00kV同施工现场外的高压架空线路的电压级别一致。
六、设计配电线路，选择导线或电缆
6.1选择总箱的进线截面及进线开关 1#变压器选择总箱的进线截面及进线开关 (1)选择导线截面： i) 按安全载流量：
上面已经计算出总计算电流Ijs = 485.36A ii) 按允许电压降：
S = 1.1×Kx×Σ(PL)/C△U = 1.1 ×0.90×10398.00/(77.00×5.00) = 26.74mm2
iii) 根据前面两条：
电缆线空气明敷，铜芯聚氯乙烯绝缘电缆线VV3×240+2×120 ，其安全载流量为567A，截面面积240mm2，能够满足使用要求。
(2)选择总进线开关：DZ10-600/3 ，其脱扣器整定电流值为Ir = 480A。 (3)选择总箱中漏电保护器：ZBM1-630/500 。 3#变压器选择总箱的进线截面及进线开关 (1)选择导线截面： i) 按安全载流量：
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