[自主解答]
π π (1)原式=cos 8π+3 +tan -4π+4
π π =cos +tan 3 4 1 3 = +1= . 2 2 (2)原式=sin(90° +2×360° )+tan(45° +2×360° )-cos 360° =sin 90° +tan 45° -1=1+1-1=1.
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[自主解答]
π π (1)原式=cos 8π+3 +tan -4π+4
π π =cos +tan 3 4 1 3 = +1= . 2 2 (2)原式=sin(90° +2×360° )+tan(45° +2×360° )-cos 360° =sin 90° +tan 45° -1=1+1-1=1.
返回