最优化理论与方法10(11)

最优化理论与方法+试卷

min ( λ ) x + λd(1) (1)

f x (1) + λ d (1)

(

)2

1 4 1 4λ = +λ = 1 2 1 2λ 2

( λ ) = 2 (1 4λ ) + (1 2λ )5 ∴ λ1 = 18 ∴ x ( 2) = x (1) + λ1d (1) 1 9 = 4 9

' ( λ ) = 16 (1 4λ ) 4 (1 2λ ) = 0