电子线路 非线性部分 第五版 谢嘉奎 课后答案
Vcm = VCEQ3 vCEmin = 1.2 VIcm = iCmax CQ3 = 240 mA
1VcmIcm2
(4) RL = 5 PL
PL
1-7
= 0I CEO = 0
PLmax(a):PLmax(b):PLmax(c)144mWPD = VCC ICQ3 = 2.3 W= PL/ PD = 6.26Icm = I CQ3 = 460 mAVcm = VCCVCEQ3 =2.25 V 517.5mWPD = VCC ICQ3 = 2.3 W= PL/ PD = 22.51VcmIcm2VCC
VCE(sat)
(1)
Icm = I CQVcm = VCEQ Icm
VCEQ Vcm = VCC IcmRC CCI
2IcmRL= VCC 2Vcm
Vcm
PLmax(a)121VCC31VCC3RL
PD1VCC 18RLVCCICQVCCIcm
PLmax(a)
C21VCC 3RL2vCE = VCC iQ(R)RLCDRLCCQ 1RC2VCEQ = VCC ICQRC AB1VCC31VCC3 RL
(2)
Vcm = VCEQ = VCC/2IcmICQPD1 6CF VCC 2RL
1VcmIcm221VCC
8RLQ PLmax(b)PDVCCICQ2VCC 2RL