2、计算: -2; (2) 3) 3 ( (1)10 (3) 1 5 2 1
(4) 1 3 3
2
1 a (6)a a a -3 =a-3b-3 1 1 1 (7)(a·) b a b ab2 ( 3)
(5) 1 10 1 3
0
(8)(a-3)2
=a(-3)×2
1 6 a
2、计算: -2; (2) 3) 3 ( (1)10 (3) 1 5 2 1
(4) 1 3 3
2
1 a (6)a a a -3 =a-3b-3 1 1 1 (7)(a·) b a b ab2 ( 3)
(5) 1 10 1 3
0
(8)(a-3)2
=a(-3)×2
1 6 a