void img6() {
int map2[14][16]; int i,j,sum=0;
int map[14][16]={
{0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0}, {0,0,0,0,0,1,1,1,1,1,1,1,0,0,0,0}, {0,0,0,0,0,1,3,2,3,2,3,1,0,0,0,0}, {0,0,0,0,0,1,2,4,4,4,2,1,0,0,0,0}, {0,0,0,0,0,1,3,4,6,4,3,1,0,0,0,0}, {0,0,0,0,0,1,2,4,4,4,2,1,0,0,0,0}, {0,0,0,0,0,1,3,2,3,2,3,1,0,0,0,0}, {0,0,0,0,0,1,1,1,1,1,1,1,0,0,0,0}, {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0}, {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0}, {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0}, {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0}, {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0}, {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0}, };
for(i=0;i<14;i++)
for(j=0;j<16;j++){
map2[i][j]=map[i][j];
if(map[i][j] == 3 || map[i][j] == 5) sum++; }
insert(map,map2,sum); }
int insert(int map[][16],int map2[][16],int sum) {
int i,j;
int x,y; //人的位置
char op; //所按下的方向键
int num = 0; //还剩下几个箱子没有推向目的地
while(1){
for(i=0;i<14;i++){
for(j=0;j<16;j++)
if(map[i][j] == 6) goto found; found:
} x = i; y = j;
system(\
num = printMap(map); if(num == sum){
printf(\你通关了....\\n\ return 0; } else{
op = getch();
if((op == 'Q') || (op =='q')){ printf(\退出....\\n\ return 2; }
op = getch(); }
switch(op) {
case 72: //上箭头
moveBox(map,x,y,1,map2); break;
case 75: //左箭头
moveBox(map,x,y,2,map2); break;
case 77: //右箭头
moveBox(map,x,y,3,map2);
break;
case 80: //下箭头
moveBox(map,x,y,4,map2); break; default:
break; } } }
int printMap(int map[][16]) {
int i,j;
int count = 0;
for(i=0;i<14;i++){
for(j=0;j<16;j++){
switch(map[i][j]){
case 0: printf(\ \ break;
case 1: color(13); printf(\■\ break;
case 2: 地
printf(\ \ break;
case 3: color(11); printf(\×\ break;
case 4: color(8);
//空地 //墙 //内部空//目的地//箱子 printf(\◎\ break;
case 5: //箱子推到目的地后显示
count++; color(9); printf(\☆\ break;
case 6: //小人 color(10); printf(\♀\ break;
} }
printf(\ }
printf(\
printf(\按方向键操作游戏，按Q退出!\\n\ return count; }
void moveBox(int map[][16],int x,int y,int select,int map2[][16]) {
int x1,y1; //下个位置的坐标 int x2,y2; //下下个位置的坐标 switch(select) {
case 1: //向上移动 x1 = x - 1; y1 = y; x2 = x - 2; y2 = y; break;
case 2: //向左移动
x1 = x; y1 = y - 1; x2 = x; y2 = y - 2; break;
case 3: //向右移动 x1 = x; y1 = y + 1; x2 = x; y2 = y + 2; break;
case 4: //向下移动 x1 = x + 1; y1 = y; x2 = x + 2; y2 = y; break; default:
break; }
//operate map
switch(map[x1][y1]){
case 1: //墙，不动 break;
case 2: if(map2[x][y] == 3){//空格，分情况变换
map[x1][y1] = 6; map[x][y] = 3; } else{
map[x1][y1] = 6; map[x][y] = 2; } break;