简支空心板桥桥墩抗震计算书(3)

2019-08-30 22:32

y (m) (m) (kN*m) 0 0.301 0.602 0.903 1.204 1.506 1.807 2.108 2.409 2.710 3.011 3.312 3.613 3.914 4.216 4.517 4.818 5.119 5.420 5.721 6.022 6.625 7.227 7.829 8.431 9.033 10.539 12.045 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2 2.2 2.4 2.6 2.8 3 3.5 4 0.00000 0.00000 1.00000 0.00000 2785.0 -0.00017 -0.00001 1.00000 0.10000 2901.2 -0.00133 -0.00013 0.99999 0.20000 3010.9 -0.00450 -0.00067 0.99994 0.30000 3108.4 -0.01067 -0.00213 0.99974 0.39998 3189.6 -0.02083 -0.00521 0.99922 0.49991 3251.3 -0.03600 -0.01080 0.99806 0.59974 3291.1 -0.05716 -0.02001 0.99580 0.69935 3307.8 -0.08532 -0.03412 0.99181 0.79854 3300.7 -0.12144 -0.05466 0.98524 0.89705 3270.5 -0.16652 -0.08329 0.97501 0.99445 3217.4 -0.22152 -0.12192 0.95975 1.09016 3142.8 -0.28737 -0.17260 0.93783 1.18342 3048.4 -0.36496 -0.23760 0.90727 1.27320 2936.1 -0.45515 -0.31933 0.86573 1.35821 2808.1 -0.55870 -0.42039 0.81504 1.43680 2679.4 -0.67629 -0.54348 0.73859 1.50695 2514.8 -0.80848 -0.69144 0.64637 1.56621 2354.3 -0.95564 -0.86715 0.52997 1.61162 2187.8 -1.11796 -1.07357 0.38503 1.63969 2017.7 -1.29535 -1.31361 0.20676 1.64628 1846.4 -1.69334 -1.90567 -0.27087 1.57538 1508.0 -2.14117 -2.66329 -0.94885 1.35201 1187.5 -2.62126 -3.59987 -1.87734 0.91679 896.3 -3.10341 -4.71748 -3.10791 0.19729 643.1 -3.54058 -5.99979 -4.68788 -0.89126 433.4 -3.91921 -9.54367 -10.34040 -5.85402 109.7 -1.61428 -11.73066 -17.91860 -15.07550 53.1 y=2.108m处,弯矩最大,My=3307.8 kN?m

垂直力: Nd=2834.4+202.5/2+?×1.5×2.108×25=

2

43028.8kN 2、截面配筋计算

偏心矩: e0=Md/Nd=3307.8/3028.8=1.092m 构件计算长度:l0=0.7×4=0.7×

?4=8.431m 0.3321

i=

IA=

??1.54/64=0.375 2??1.5/4 l0/i=8.431/0.375=22.48>17.5 ∴应考虑偏心矩增大系数η η=1+

l1(0)2?1?2

1400e0/h0hh0=r+rs=0.75+0.66=1.41m h=2r=2×0.75=1.5m

ξ1=0.2+2.7e0=0.2+2.7×1.092=1.09>1.0

h01.41∴取 ξ1=1.0

ξ2=1.15-0.01

1.094〉1.0 ∴取 ξ2=1.0

η=1+

18.4312()?1.0?1.0=1.029

1400?1.092/1.411.5l0h=1.15-0.01×

8.4311.5

ηe0=1.029×1.092=1.124m

由公路钢筋混凝土及预应力混凝土桥涵设计规范(JTG D62-2004)附录C有 配筋率 ρ=

fcdBr?Ae0 ?fsd'Ce0?Dgrfcd=11.5MPa fsd’ =280MPa

g=rs/r=0.66/0.75=0.88 假定ξ=0.32,

A=0.6351,B=0.4433,C=-0.8656,D=1.7721 ρ=11.5?0.4433?0.75?0.6351?1.124280?0.8656?1.124?1.7721?0.88?0.75=0.00731

N2

2

d≤Arfcd+Cρrfsd’

Ar2

f2

2

cd+Cρrfsd’=0.6351×0.75×11.5×

103

-0.8656×0.00731×0.752

×280×103

=3111.7kN>Nd=3028.8Kn ∴纵向钢筋面积

A2

s=ρπr=0.00731×π×0.752

=0.01292m

2

选用28φ25HRB335钢筋,A=0.001374m2

> As=0.01292m2


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