z2=@if(c22 #le# 60, 5,0)*@abs(60-c22); end
Linearization components added: Constraints: 38 Variables: 28 Integers: 14
Local optimal solution found.
Objective value: 183.3333 Extended solver steps: 0 Total solver iterations: 11
Variable Value Reduced Cost
Z1 183.3333 0.000000
Z2 0.000000 0.000000
C1 1.000000 0.000000
C12 63.33333 0.000000
C2 0.7752475 0.000000
C22 60.00000 0.000000
Row Slack or Surplus Dual Price
1 183.3333 -1.000000
2 0.000000 -1.066667
3 0.000000 0.000000
4 0.000000 1072.000
5 0.2247525 0.000000
6 183.3333 0.000000
7 0.000000
10
-1.000000
8 -1.000000
9 0.000000
0.000000 0.000000
11