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2019-08-31 09:14

µç»¯Ñ§A´ð°¸ Ò»¡¢Ñ¡ÔñÌâ

1. (A) 2. (D) 3. (A) , µç³Ø·´Ó¦¶¼Ïàͬ£¬E = E4. (D)

5. (D)

= 1.229 V

6. (D) Ïà¹ØÀë×ÓŨ¶ÈÔ½´ó£¬À©É¢²ãºñ¶ÈԽС¡£

7. (D) 8. (B) 9. (B) 10 (B) ¶þ¡¢Ìî¿ÕÌâ

11. Pt,H2(g)|HI(aq)|I2(s),Pt

12. Zn(s)©¦ZnCl2(m1)¡¬AgNO3(m2)©¦Ag(s) KNO3 ÑÎÇÅ (»ò NH4NO3ÑÎÇÅ) 13. ·Ç×Ô·¢, E= -0.0295 V

14. Pt©¦Sn4+,Sn2+¡¬Fe3+,Fe2+©¦Pt E?£½0.62 V 15. Pt,O2(g)|OH ¨C(aq)|Ag2O(s)|Ag(s)

16. Pt,Cl2(p?)|Cl -(a1)||Cl -(a2)|Cl2(p?),Pt 17. I, ¶ÔÏû

18. E?= 0.323 V K?= 8.46¡Á1010 19. E3?=2E1? - E2?

20. 2Ag(s)£«Cu2+£«2Cl-©¤¡úCu(s)£«2AgCl(s) 2Ag(s)£«Cu2+©¤¡úCu(s)£«2Ag+(aq)

Èý¡¢¼ÆËãÌâ 21. [´ð]

??????m(AgBr)??m(Ag)??m(Br)?140.32¡Á10

-4

S?m2?mol-1

c(AgBr)/mol?dm-3?(Ksp)2?7.937?10?7

1

c(AgBr)?7.937?10?7mol?dm-3?7.937?10?4mol?m-3

?5-1?(AgBr)???m(AgBr)c(AgBr)?1.113?10S?m

?(AgBrÈÜÒº)??(AgBr)??c(H2O)?1.663?10?5S?m-1

122. [´ð] O2+H2O+2e- ©¤©¤¡ú 2OH-

2 ? (O2/OH-)=? ? (O2/OH-)-(RT/F)ln? (OH-)

=? ? (O2/OH-)-(RT/F)lnKw+(RT/F)ln? (H+) ? (O2/OH-)=1.227-0.059pH

24. [´ð] Ksp= a+a- = (?? )2(c/c?)2 ?? = (Ksp)1/2 /(c/c?)

²»º¬ NaCl µÄ TiCl ±¥ºÍÈÜÒºÖÐ ?? = (Ksp)1/2 /(c/c?) = 0.885

ÔÚ 0.1000 mol¡¤dm-3 NaCl ÈÜÒºÖÐ

??cc2Ksp?a?a????0??0???[3.95?10?3(0.1?3.95?10?3)]

cc?? =

25. [´ð]

Ksp1/2[3.95?10?3(0.1?3.95?10?3)]1/2 = 0.702

Ag+ + 2NH3 ¡ú [Ag(NH3)2]+

0.001 0.1

¿ªÊ¼/mol?kg?1

ƽºâ/mol?kg?1

K(²»Îȶ¨)? x

?320.098+2x

0.001 ¨C x

2aAg?aNH3a(Ag(NH))aAg?6?10?8?0.001??6.25?10?9 2(0.098)E(Ag?|Ag)?0.799 V?RTlnaAg??0.314 V F[´ð]

Ag+

+ 2CN - ¡ú [Ag(CN)2] -

¿ªÊ¼/mol?kg?1 ƽºâ/mol?kg?1

0.001 0.1 x

0.098+2x

0.001 ¨C x

x(0.098)2 K(²»Îȶ¨)??0.001a(Ag(CN)?)2aAg??3.96?10?20

2aAg?aCN-

E(Ag?|Ag)?0.799 V?RTlnaAg???0.348 V F26. [´ð] ?m(NaCl) = ?m(Na+) + ?m(Cl-) = [U(Na+) + U(Cl-)]F = 106.73 S¡¤m2¡¤mol-1 k(NaCl) = ?m(NaCl)c(NaCl) = 1.07¡Á10-4 S¡¤m-1


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