}
cout << \system(\
static int x = 12; int f1(int a) { }
检测静态局部变量和局部变量的作用 static int y = 300; y = y + a;
cout << \return y;
5.
#include
cout << \输出该数的逆转数为: do{ d = x % 10; cout << d;
x = x / 10;
} while (x != 0); cout << endl;
}
void main() { int n;
cout << \输入一个正整数:\ cin >> n; f1(n);
system(\} \
二.编程题
1.
#include
int maxtemp;
for (int x = 1; x < a; x++) { }
cout<<\以内能被13整除的最大数为:\if (x % 13 == 0)
maxtemp = x;
maxtemp< void main() { } int const m = 100; maxdr(m); system(\ 2. #include } int a = 1; int sum = 0; while (a <= m) { } return sum; int fac = 1; for (int b = 1; b <= a; b++) fac *= b; sum += fac; a++; void main() { } int n; cout << \请输入一个值,计算它的阶乘和值:\cin >> n; cout << endl << \它的阶乘和值为:\system(\