2017年电大2017秋高等数学基础形成性作业考核答案(2)

2020-04-14 00:29

则定义域为?x|x?0或x???1?? 2?⒊在半径为R的半圆内内接一梯形,梯形的一个底边与半圆的直径重合,另一底边的两个端点在半圆上,试将梯形的面积表示成其高的函数. 解: D

A R O h E

B C

设梯形ABCD即为题中要求的梯形,设高为h,即OE=h,下底CD=2R 直角三角形AOE中,利用勾股定理得

AE?OA2?OE2?R2?h2 则上底=2AE?2R2?h2 h?2R?2R2?h2?hR?R2?h2 2sin3x⒋求lim.

x?0sin2xsin3xsin3x?3xsin3x3133解:lim?lim3x?lim3x?=??

x?0sin2xx?0sin2xx?0sin2x2122?2x2x2xx2?1⒌求lim.

x??1sin(x?1)故S?????x2?1(x?1)(x?1)x?1?1?1?lim?lim???2 解:limx??1sin(x?1)x??1sin(x?1)x??1sin(x?1)1x?1tan3x⒍求lim.

x?0xtan3xsin3x1sin3x11?lim??lim??3?1??3?3 解:limx?0x?0xxcos3xx?03xcos3x11?x2?1⒎求lim.

x?0sinx1?x2?1(1?x2?1)(1?x2?1)x2?lim?lim解:lim2x?0x?0x?0sinx(1?x?1)sinx(1?x2?1)sinx ?limx?0

x(1?x2?1)sinxx?0?0

?1?1??1⒏求lim(x??x?1x). x?3111(1?)x[(1?)?x]?1x?1xe?1x?4xx?x解:lim( )?lim()?lim?lim??ex3x??x?3x??x??33xx??e11?(1?)[(1?)3]3xxx3x2?6x?8⒐求lim2.

x?4x?5x?4x2?6x?8?x?4??x?2??limx?2?4?2?2

解:lim2?limx?4x?5x?4x?4?x?4??x?1?x?4x?14?131?⒑设函数

?(x?2)2,x?1?f(x)??x,?1?x?1

?x?1,x??1?讨论f(x)的连续性,并写出其连续区间. 解:分别对分段点x??1,x?1处讨论连续性 (1)

x??1?x??1?limf?x??limx??1x??1?x??1?limf?x??lim?x?1???1?1?0x??1?x??1?

所以limf?x??limf?x?,即f?x?在x??1处不连续 (2)

x?1?x?1?limf?x??lim?x?2???1?2??1x?1?x?1?22limf?x??limx?1f?1??1

所以limf?x??limf?x??f?1?即f?x?在x?1处连续

x?1?x?1?由(1)(2)得f?x?在除点x??1外均连续 故f?x?的连续区间为???,?1????1,???

【高等数学基础】形考作业2答案:

第3章 导数与微分

(一)单项选择题

f(x)f(x)?(C ). 存在,则limx?0x?0xx A. f(0) B. f?(0) C. f?(x) D. 0cvx

f(x0?2h)?f(x0)?(D ). ⒉设f(x)在x0可导,则limh?02h A. ?2f?(x0) B. f?(x0) C. 2f?(x0) D. ?f?(x0)

⒈设f(0)?0且极限limf(1??x)?f(1)?(A ).

?x?0?x A. e B. 2e

⒊设f(x)?e,则limx11e D. e 24 ⒋设f(x)?x(x?1)(x?2)?(x?99),则f?(0)?(D ).

C.

A. 99 B. ?99 C. 99! D. ?99! ⒌下列结论中正确的是( C ).

A. 若f(x)在点x0有极限,则在点x0可导. B. 若f(x)在点x0连续,则在点x0可导. C. 若f(x)在点x0可导,则在点x0有极限. D. 若f(x)在点x0有极限,则在点x0连续.

(二)填空题

1?2xsin,x?0? ⒈设函数f(x)??,则f?(0)? 0 . x?x?0?0,df(lnx)2lnx5. ⒉设f(ex)?e2x?5ex,则??xxdx1 ⒊曲线f(x)?x?1在(1,2)处的切线斜率是k?

2π22? ⒋曲线f(x)?sinx在(,1)处的切线方程是y?x?(1?)

4224 ⒌设y?x2x,则y??2x2x(1?lnx)

1 ⒍设y?xlnx,则y???

x(三)计算题

⒈求下列函数的导数y?:

3x⑴y?(xx?3)e y??(x?3)e?x2e

222⑵y?cotx?xlnx y???cscx?x?2xlnx

xx3212xlnx?xx2⑶y? y??

ln2xlnxcosx?2xx(?sinx?2xln2)?3(coxs?2x)⑷y? y?? 34xx

1sinx(?2x)?(lnx?x2)cosxlnx?xx⑸y? y?? 2sinxsinx2

4⑹y?x?sinxlnx y??4x?3sinx?cosxlnx x

sinx?x23x(cosx?2x)?(sinx?x2)3xln3⑺y? y?? x32x3

ex1x??⑻y?etanx?lnx y??etan 2cosxxxx

⒉求下列函数的导数y?: ⑴y?e1?x2

y??e

1?x2x1?x2

⑵y?lncosx3

?sinx32y??3x??3x2tanx3 3cosx ⑶y?78xxx

?17y?x y??x8

8

⑷y?3x?x

1?2?111y??(x?x2)3(1?x2)

32

⑸y?cose

2xy???exsin(2ex)

y?cosex2x2

x2y???2xesine

⑺y?sinxcosnx

n

y??nsinn?1xcosxcosnx?nsinnxsin(nx)

y?5sinx2

y??2xln5cosx5 ⑼

2sinx2

y?esin2x

y??sin2xe ⑽

sin2x

y?x?ex2x2x2

y??x(x?2xlnx)?2xe ⑾

x2

y?xexex?eex

y??xexxex(?elnx)?eexx

⒊在下列方程中,y?y(x)是由方程确定的函数,求y?: ⑴ycosx?e2y

y?cosx?ysinx?2e2yy?

ysinxy?? 2ycosx?2e

⑵y?cosylnx

1y??siny.y?lnx?cosy.

xcosyy??

x(1?sinylnx)

x2⑶2xsiny?

y


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