二分法及迭代法求解非线性方程根(3)

val =

1.5052

n =

24

>> val=DieDai('Exp2',1,1e-6)

跌代次数8

val =

-2.9475

>> val=DieDai('Exp3',1,1e-6)

跌代次数10

val =

1.5052

>> val=DieDai('Exp4',1,1e-6)

跌代次数

6

val =

Inf

>> NewtonDieDai('fun1','Exp4',1,1e-6)

x1 =

1.5377

n =

2

x1 =

1.5059

n =

3

x1 =

1.5052

n =

4

x1 =

1.5052

n =

5

跌代次数

5

ans =

1.5052

>>