数字电子技术课后习题及答案(2)

2018-11-17 19:33

?(A?B)C

?(A?B?C)AB?BC?CA

得证。

(4)A?B?C?ABC

证明: 等式右侧

?ABC?(A?B?C)?AB?BC?CA

?ABC?A?AB?BC?CA?B?AB?BC?CA?C?AB?BC?CA ?ABC?A?B?BC?C?B?A?C?AC?C?AB?B?A?ABC?A?B?C?B?A?C?C?B?A ?ABC?ABC?ABC?ACB

(AB?AB)?C 等式左侧?

?(AB?AB)C?(AB?AB)C ?(AB?AB)C?(AB?AB)C

?ABC?ABC?ABC?ABC ?ABC?ABC?ACB?A?B?C 比较左右两侧,得证。 (5)ABC

证明:

(AB?AB)?C 等式右侧?

?(AB?AB)C?(AB?AB)C ?(AB?AB)C?(AB?AB)C

?ABC?ABC?ABC?ABC

得证。

(6)A(C?D)?BCD?ACD?ABCD?C?D

证明: 等式左侧

?A(CD?CD)?(B?AB)CD?ACD

?A(CD?CD)?(A?B)CD?ACD

?A(CD?CD)?ACD?BCD?ACD ?A(CD?CD)?A(CD?CD)?BCD

?CD?CD?BCD

?CD?(1?B)CD

?CD?CD

?C?D

得证。

2.6 根据对偶规则,求出下列函数的对偶。

(1)L?

A(B?C)?A(B?C)

解:L??(A?BC)(A?BC)

(2)L?A(B?C)?AB(C?D)?ABC?D

解:L??(A?BC)(A?B)CD?(A?B?C)?D

(3)L

?AB?BC?CA

解:L??(A?B)(B?C)(C?A)

(4)L?(A?C)(A?B?C)(B?C)(A?B?C)

解:L??AC?ABC?BC?ABC

2.7 根据反演规则,求出下列函数的反函数

(1)L?(A?BC)DE

解:L?A?BC?DE

(2)L?[A?(BC?CD)E]F

解:L?A?(BC?CD)E?F (3)L

?A?B?CD?C?D?AB 解:L?(A?B?CD)(C?D?AB)

(4)L?AB?ABC(A?BC)

解:L?AB?ABC另解:(1)L(2)L(3)L(4)L?A?BC

?A?B?C??D?E ??F ?A?B?CC?D?E???????AB?C?D??CD??A?B? ?A?B?A?B?C??A?B?C?

2.8 将下列函数变换为最小项之和的表达式

(1)L?AB?AC?BC

解:L?AB(C?C)?AC(B?B)?BC(A?A)

?ABC?ABC?ABC?ABC?ABC?ABC

L?ABC?ABC?ABC?ABC??m?3,5,6,7?

(2)L?BC?AB?AC 解:L?BC(A?A)?AB(C?C)?AC(B?B)

?ABC?ABC?ABC?ABC?ABC?ABC

L?ABC?ABC?ABC?ABC?ABC?ABC??m?0,1,3,4,6,7?

(3)L?(A?B)AB?BC

?(A?B)(AB?BC)

?(A?B)(A?B)(B?C)

?(A?A?A?B?AB?B?B)(B?C) ?(A?B?AB)(B?C)

?(A?B?AB)(B?C)

?A?B?B?AB?A?B?C?ABC ?AB?ABC?ABC

?AB(C?C)?ABC?ABC

?ABC?ABC?ABC

L?ABC?ABC?ABC??m?3,4,5?

(4)L?(A?B?C)?A?B?C (A?B)C 解:L?(A?B?C)??A?B?C?AC?BC

?A(B?B)?B(A?A)?C(A?A)?AC?BC

?AB?AB?AB?AB?AC?AC?AC?BC ?AB?AB?AB?AC?AC

?AB(C?C)?AB(C?C)?AB(C?C)?AC(B?B)?AC(B?B)?ABC?ABC?ABC?ABC?ABC?ABC?ABC?ABC?ABC?ABC?ABC?ABC?ABC?ABC?ABC?ABC?ABC

L?ABC?ABC?ABC?ABC?ABC?ABC?ABC??m?1,2,3,4,5,6,7?

2.9 用卡诺图化简下列逻辑函数为最简与或表达式 (1)

L?AB?BC?AC?BC 解:直接在卡诺图上填写对应的各项。如图2.9-1所示。

图2.9-1

(2)

L?B?AC

L?AC?AC?BC?BC

解:直接在卡诺图上填写对应的各项。如图2.9-2所示。

图2.9-2

化简结果:L?AB?AC?BC

(3) L?AB?BD?BCD?ABCD 解:直接在卡诺图上填写对应的各项。如图2.9-3所示。

图2.9-3


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