end k=k+1; end end end for i=1:k-2 S(i)=S(i+1); end
Smin=min(S);%最小平均距离 wz=L2;%缴费站的位置 fprintf('最小平均距离:') disp(Smin)
fprintf('缴费站的位置:')
disp(wz)
模拟程序二
clc clear n=24; a=zeros(n);
a(1,3)=24;a(1,18)=20;a(1,23)=16; a(2,23)=18;a(2,22)=22;a(2,9)=28; a(3,5)=9;a(3,19)=10;a(3,4)=11;a(3,22)=15; a(4,16)=9;a(4,18)=8; a(5,19)=6;a(5,6)=8;a(5,20)=9;
a(6,7)=11;a(6,24)=11;a(6,12)=10;a(6,20)=14;a(6,22)=11; a(7,9)=10;a(7,22)=15;
a(8,15)=19;a(8,11)=11;a(8,13)=15;a(8,24)=8; a(9,15)=19;a(9,24)=25; a(10,12)=8;a(10,14)=6;a(10,20)=8; a(11,13)=12;a(11,15)=23; a(12,24)=10;a(12,13)=9; a(13,14)=6;
a(16,17)=7;a(16,21)=10; a(17,18)=12; a(19,21)=7; a(20,21)=15; a(22,23)=8; a=a+a';
% Floyd算法求每对顶点之间的最短距离 M=max(max(a))*n^2;% M为充分大的正实数 d=a+((a==0)-eye(n))*M; path=zeros(n); for k=1:n
for i=1:n for j=1:n
if d(i,j)>d(i,k)+d(k,j) d(i,j)=d(i,k)+d(k,j); path(i,j)=k; end end end end
%确定派出所的位置 L=[];L1=[];L2=[];S=[]; c=1; for x=1:24 for y=1:24 for z=1:24 for n=1:24 L(1)=d(n,x); L(2)=d(n,y); L(3)=d(n,z); L1(n)=min(L); end b=1:n; if(L1(b)<=25) L2(1)=x; L2(2)=y; L2(3)=z; wz{c}=L2; S(c)=sum(L1); c=c+1; end end end end
c=find(S==min(S)); wz=wz{c(1)};%派出所位置 fprintf('派出所位置 :')
disp(wz)
模拟程序三 第一组： model: sets:
city/1,2,6,7,9,22,23/:u; links(city,city):dist,x;
endsets data:
dist=
0
34 35 39 49 24 16
33 37 28 22 18
11 21 11 19
10 15 23
25 33
8 0;
34 0
35 33 0
39 37 11 0
49 28 21 10 0
24 22 11 15 25 0 16 18 19 23 33 8
enddata
n=@size(city);
min=@sum(links:dist*x);
@for(city(k):@sum(city(i)|i#ne#k:x(i,k))=1; @sum(city(j)|j#ne#k:x(k,j))=1;);
@for(city(i):@for(city(j)|j#gt#1#and#i#ne#j:u(i)-u(j)+n*x(i,j)<=n-1);); @for(city(i):u(i)<=n-1); @for(links:@bin(x)); end
第二组： model: sets:
city/3,4,5,16,17,18,19,20,21,22/:u; links(city,city):dist,x; endsets data:
dist=
0 11 9 20 27 19 10 18 17 15 11 0 20 9 16 8 21 29 19 26 9 20 0 23 30 28 6 9 13 19 20 9 23 0 7 17 17 25 10 35 27 16 30 7 0 12 24 32 17 42 19 8 28 17 12 0 29 37 27 34 10 21 6 17 24 29 0 15 7 25 18 29 9 25 32 37 15 0 15 25 17 19 13 10 17 27 7 15 0 32 15 26 19 35 42 34 25 25 32 0;
enddata
n=@size(city);
min=@sum(links:dist*x);
@for(city(k):@sum(city(i)|i#ne#k:x(i,k))=1; @sum(city(j)|j#ne#k:x(k,j))=1;);
@for(city(i):@for(city(j)|j#gt#1#and#i#ne#j:u(i)-u(j)+n*x(i,j)<=n-1);); @for(city(i):u(i)<=n-1); @for(links:@bin(x)); end