matlab实现jpeg算法进行图像压缩的源代码(2)

2018-12-21 12:05

% get input matrix size N = size(in,1);

% build the matrix n = 0:N-1; for k = 0:N-1 if (k>0)

C(k+1,n+1) = cos(pi*(2*n+1)*k/2/N)/sqrt(N)*sqrt(2); else

C(k+1,n+1) = cos(pi*(2*n+1)*k/2/N)/sqrt(N); end end

out = (C')*in*C; %

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% plot_bases - use the inverse DCT in 2 dimensions to plot the base pictures %

% Note: we can get resolution be zero pading of the input matrix !!! % that is by calling: in = zeros(base_size*resolution) % where: resolution is an integer > 1 % So I will use zero pading for resolution (same as in the fourier theory) % instead of linear interpolation. %

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function plot_bases( base_size,resolution,plot_type )

figure;

for k = 1:base_size for l = 1:base_size

in = zeros(base_size*resolution); in(k,l) = 1; % \for the \(k,l)\ subplot( base_size,base_size,(k-1)*base_size+l ); switch lower(plot_type)

case 'surf3d', surf( pdip_inv_dct2( in ) ); case 'mesh3d', mesh( pdip_inv_dct2( in ) );

case 'mesh2d', mesh( pdip_inv_dct2( in ) ); view(0,90); case 'gray2d', imshow( 256*pdip_inv_dct2( in ) ); end axis off; end end

% add a title to the figure

subplot(base_size,base_size,round(base_size/2));

h = title( 'Bases of the DCT transform (section 1.3)' ); set( h,'FontWeight','bold' ); %

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% image_8x8_block_dct - perform a block DCT for an image %

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function transform_image = image_8x8_block_dct( input_image )

transform_image = zeros( size( input_image,1 ),size( input_image,2 ) ); for m = 0:15 for n = 0:15

transform_image( m*8+[1:8],n*8+[1:8] ) = ...

pdip_dct2( input_image( m*8+[1:8],n*8+[1:8] ) ); end end %

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% image_8x8_block_inv_dct - perform a block inverse DCT for an image %

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function restored_image = image_8x8_block_inv_dct( transform_image )

restored_image =

zeros( size( transform_image,1 ),size( transform_image,2 ) ); for m = 0:15 for n = 0:15

restored_image( m*8+[1:8],n*8+[1:8] ) = ...

pdip_inv_dct2( transform_image( m*8+[1:8],n*8+[1:8] ) ); end end %

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% calc_snr - calculates the snr of a figure being compressed %

% assumption: SNR calculation is done in the following manner: % the deviation from the original image is considered % to be the noise therefore: %

% noise = original_image - compressed_image %

% the SNR is defined as: %

% SNR = energy_of_image/energy_of_noise %

% which yields: %

% SNR =

energy_of_image/((original_image-compressed_image)^2) %

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function SNR = calc_snr( original_image,noisy_image )

original_image_energy = sum( original_image(:).^2 );

noise_energy = sum( (original_image(:)-noisy_image(:)).^2 ); SNR = original_image_energy/noise_energy;

以下是1-9号原图像,放到matlab的.m文件目录里,重命名9个图像名为1、2、3、4、5、6、7、8、9


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