50道SQL(2)

2018-12-24 00:06

SELECT SC.C# as 课程ID, Cname as 课程名称

,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85] ,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70] ,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60] ,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -] FROM SC,Course

where SC.C#=Course.C# GROUP BY SC.C#,Cname;

24、查询学生平均成绩及其名次

SELECT 1+(SELECT COUNT( distinct 平均成绩) FROM (SELECT S#,AVG(score) AS 平均成绩 FROM SC GROUP BY S# ) AS T1

WHERE 平均成绩 > T2.平均成绩) as 名次, S# as 学生学号,平均成绩

FROM (SELECT S#,AVG(score) 平均成绩 FROM SC GROUP BY S# ) AS T2

ORDER BY 平均成绩 desc;

25、查询各科成绩前三名的记录:(不考虑成绩并列情况) SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数 FROM SC t1

WHERE score IN (SELECT TOP 3 score FROM SC

WHERE t1.C#= C# ORDER BY score DESC )

ORDER BY t1.C#;

26、查询每门课程被选修的学生数

select ,count(S#) from sc group by C#;

27、查询出只选修了一门课程的全部学生的学号和姓名 select SC.S#,Student.Sname,count(C#) AS 选课数 from SC ,Student where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1;

28、查询男生、女生人数

Select count(Ssex) as 男生人数 from Student group by Ssex having Ssex='男';

Select count(Ssex) as 女生人数 from Student group by Ssex having Ssex='女';

29、查询姓“张”的学生名单

SELECT Sname FROM Student WHERE Sname like '张%';

30、查询同名同性学生名单,并统计同名人数

select Sname,count(*) from Student group by Sname having count(*)>1;

31、1981年出生的学生名单(注:Student表中Sage列的类型是datetime) select Sname, CONVERT(char (11),DATEPART(year,Sage)) as age from student

where CONVERT(char(11),DATEPART(year,Sage))='1981';

32、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列

Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ;

33、查询平均成绩大于85的所有学生的学号、姓名和平均成绩 select Sname,SC.S# ,avg(score) from Student,SC

where Student.S#=SC.S# group by SC.S#,Sname having avg(score)>85;

34、查询课程名称为“”,且分数低于60的学生姓名和分数 Select Sname,isnull(score,0) from Student,SC,Course

where SC.S#=Student.S# and SC.C#=Course.C# and Course.Cname='数据库'and score <60;

35、查询所有学生的选课情况; SELECT SC.S#,SC.C#,Sname,Cname FROM SC,Student,Course

where SC.S#=Student.S# and SC.C#=Course.C# ;

36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数; SELECT distinct student.S#,student.Sname,SC.C#,SC.score FROM student,Sc

WHERE SC.score>=70 AND SC.S#=student.S#;

37、查询不及格的课程,并按课程号从大到小排列

select c# from sc where scor e <60 order by C# ;

38、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名;

select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score>80 and C#='003';

39、求选了课程的学生人数 select count(*) from sc;

40、查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩 select Student.Sname,score

from Student,SC,Course C,Teacher

where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname='叶平' and SC.score=(select max(score)from SC where C#=C.C# );

41、查询各个课程及相应的选修人数 select count(*) from sc group by C#;

42、查询不同课程成绩相同的学生的学号、课程号、学生成绩

select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# <>B.C# ;

43、查询每门功成绩最好的前两名

SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数 FROM SC t1

WHERE score IN (SELECT TOP 2 score FROM SC

WHERE t1.C#= C# ORDER BY score DESC )

ORDER BY t1.C#;

44、统计每门课程的学生选修人数(超过10人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,查询结果按人数降序排列,若人数相同,按课程号升序排列

select C# as 课程号,count(*) as 人数 from sc group by C#

order by count(*) desc,c#

45、检索至少选修两门课程的学生学号 select S# from sc group by s#

having count(*) > = 2

46、查询全部学生都选修的课程的课程号和课程名 select C#,Cname from Course

where C# in (select c# from sc group by c#)

47、查询没学过“叶平”老师讲授的任一门课程的学生姓名

select Sname from Student where S# not in (select S# from

Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='叶平');

48、查询两门以上不及格课程的同学的学号及其平均成绩

select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC where score <60 group by S# having count(*)>2)group by S#;

49、检索“004”课程分数小于60,按分数降序排列的同学学号

select S# from SC where C#='004'and score <60 order by score desc;

50、删除“002”同学的“001”课程的成绩 delete from Sc where S#='001'and C#='001';

13题待修改? update

(select s.score from SC s,Course c ,Teacher t where s.c#=c.c# and c.t#=t.t# and t.Tname='叶平')ss set

ss.score=

(select avg(score) from SC where c#=(select s1.c# from SC s1,Course c1 ,Teacher t1 where s1.c#=c1.c# and c1.t#=t1.t# and t1.Tname='叶平'));


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