碎纸片的拼接复原算法及MATLAB实现(6)

2019-01-05 10:56

[y,n,flag1]=f3(a,p,n); end

while (flag1~=0|flag~=0)&length(y(1,:))

[y,n,flag]=f2(a,y,n); % fwrite(f1,y,n,'int'); else

[y,n,flag1]=f3(a,y,n); % fwrite(f1,y,n,'int'); end end

(11) pinjie2()函数代码 function pinjie2() a=read2();

[x,x1,x2]=size(a);

p(:,:)=a(1,:,:); n=[1];

[y,n,flag]=f2(a,p,n);

flag1=1; if flag==0

[y,n,flag1]=f3(a,p,n); end

while (flag1~=0|flag~=0)&length(y(1,:))

[y,n,flag]=f2(a,y,n); % fwrite(f1,y,n,'int'); else

[y,n,flag1]=f3(a,y,n); % fwrite(f1,y,n,'int'); end end

(12) pinjie3()函数代码 function pinjie3()

24

a=read3(); [x,x1,x2]=size(a); p(:,:)=a(1,:,:); n=[1];

[y,n,flag]=f2(a,p,n); flag1=1; if flag==0

[y,n,flag1]=f3(a,p,n); end

while (flag1~=0|flag~=0)&length(y(1,:))

[y,n,flag]=f2(a,y,n); % fwrite(f1,y,n,'int'); else

[y,n,flag1]=f3(a,y,n); % fwrite(f1,y,n,'int'); end end y1=y'; q=length(n); q1=int16(x/q); t=ones(q1,q*x2,x1); t(1,:,:)=y1; C=a;

[x,x1,x2]=size(a); c=1:1:x; for k=2:q1

[c,C]=ff(C,c,n); [x,x1,x2]=size(C); p(:,:)=C(1,:,:); n=[1];

[y,n,flag]=f2(C,p,n); flag1=1; if flag==0

[y,n,flag1]=f3(C,p,n); end

while (flag1~=0|flag~=0)&length(y(1,:))

25

if flag==1

[y,n,flag]=f2(C,y,n); % fwrite(f1,y,n,'int'); else

[y,n,flag1]=f3(C,y,n); % fwrite(f1,y,n,'int'); end end y1=y'; t(k,:,:)=y1; end

pin=pinjie3(t); pin_=pin';

imwrite(pin_,'d:\\pp.bmp'); a=t;

[x,x1,x2]=size(a); p(:,:)=a(1,:,:); n=[1];

[y,n,flag]=f2(a,p,n); flag1=1; if flag==0

[y,n,flag1]=f3(a,p,n); end

while (flag1~=0|flag~=0)&length(y(1,:))

[y,n,flag]=f2(a,y,n); % fwrite(f1,y,n,'int'); else

[y,n,flag1]=f3(a,y,n); % fwrite(f1,y,n,'int'); end end

(13) pinjie4()函数代码 function pinjie4() a=read4(); [x,x1,x2]=size(a);

26

p(:,:)=a(1,:,:); n=[1];

[y,n,flag]=f2(a,p,n); flag1=1; if flag==0

[y,n,flag1]=f3(a,p,n); end

while (flag1~=0|flag~=0)&length(y(1,:))

[y,n,flag]=f2(a,y,n); % fwrite(f1,y,n,'int'); else

[y,n,flag1]=f3(a,y,n); % fwrite(f1,y,n,'int'); end end y1=y'; q=length(n); q1=int16(x/q); t=ones(q1,q*x2,x1); t(1,:,:)=y1; C=a;

[x,x1,x2]=size(a); c=1:1:x; for k=2:q1

[c,C]=ff(C,c,n); [x,x1,x2]=size(C); p(:,:)=C(1,:,:); n=[1];

[y,n,flag]=f2(C,p,n); flag1=1; if flag==0

[y,n,flag1]=f3(C,p,n); end

while (flag1~=0|flag~=0)&length(y(1,:))

27

[y,n,flag]=f2(C,y,n); % fwrite(f1,y,n,'int'); else

[y,n,flag1]=f3(C,y,n); % fwrite(f1,y,n,'int'); end end y1=y'; t(k,:,:)=y1; end

pin=pinjie3(t); pin_=pin';

imwrite(pin_,'d:\\pp.bmp'); a=t;

[x,x1,x2]=size(a); p(:,:)=a(1,:,:); n=[1];

[y,n,flag]=f2(a,p,n); flag1=1; if flag==0

[y,n,flag1]=f3(a,p,n); end

while (flag1~=0|flag~=0)&length(y(1,:))

[y,n,flag]=f2(a,y,n); % fwrite(f1,y,n,'int'); else

[y,n,flag1]=f3(a,y,n); % fwrite(f1,y,n,'int'); end end

28


碎纸片的拼接复原算法及MATLAB实现(6).doc 将本文的Word文档下载到电脑 下载失败或者文档不完整,请联系客服人员解决!

下一篇:广东省2013年中考语文复习专题检测试题(含答案)共163页 2

相关阅读
本类排行
× 注册会员免费下载(下载后可以自由复制和排版)

马上注册会员

注:下载文档有可能“只有目录或者内容不全”等情况,请下载之前注意辨别,如果您已付费且无法下载或内容有问题,请联系我们协助你处理。
微信: QQ: