C语言练习册答案_(2010)(3)

}

printf(\的逆序数为%d\\n\

if(n>=100&&n<=999)

{

printf(\是3位数\\n\n1=n; n2=(n/10); n3=n/100;

printf(\每一位上的数字是(从高到低)%d,%d,%d\\n\

nn=n1*100+n2*10+n3;

}

printf(\的逆序数为%d\\n\

if(n>=10&&n<=99)

{

printf(\是2位数\\n\n1=n; n2=n/10;

printf(\每一位上的数字是(从高到低)%d,%d\\n\

nn=n1*10+n2;

}

printf(\的逆序数为%d\\n\

if(n>=0&&n<=9)

{

printf(\是1位数\\n\

printf(\每一位上的数字是(从高到低)%d\\n\

11

nn=n;

}

}

printf(\的逆序数为%d\\n\

6、#include main() {

float i,r;

printf(\万元)：\scanf(\if(i<=10)

r=i*0.1;

else if(i<=20)

r=10*0.1+(i-10)*0.075;

else if(i<=40)

r=10*0.1+10*0.075+(i-20)*0.05;

else if(i<=60)

r=10*0.1+10*0.075+20*0.05+(i-40)*0.03;

else if(i<=100)

r=10*0.1+10*0.075+20*0.05+20*0.03+(i-60)*0.015;

else

r=10*0.1+10*0.075+20*0.05+20*0.03+40*0.015+(i-100)*0.01; }

7、#include #include void main()

{ double s=0.0;

12

printf(\

int i,n;

scanf(\ for(i=0; i

if(i%5==0 && i==0)s=s+i; s=sqrt(s);

printf(\

8、#include main()

{ int n,g,sh;

printf(\：\ scanf(\

printf(\ if(n>=10 && n<=19) switch(n)

{ case 10:printf(\

case 11: printf(\ case 12:printf(\ case 13:printf(\ case 14:printf(\ case 15:printf(\ case 16:printf(\ case 17:printf(\ case 18:printf(\ case 19:printf(\ } else {

g=n; sh=n/10; switch(sh) {

case 2: printf(\ case 3:printf(\ case 4:printf(\ case 5:printf(\ case 6:printf(\ case 7:printf(\ case 8:printf(\

13

case 9:printf(\ }

switch(g) {

case 0:printf(\ case 1:printf(\ case 2:printf(\ case 3:printf(\

} } }

14

case 4:printf(\ case 5:printf(\ case 6:printf(\ case 7:printf(\ case 8:printf(\ case 9:printf(\第3节 循环结构程序设计

一、选择题

题号 答案 题号 答案 题号 答案 题号 答案 1 2 3 4 B 14 5 6 7 8 9 10 B 11 A 12 B 13 A 15 B 16 C 17 C 27 D 18 B 19 B 20 A 21 B 22 A 23 A 24 C 25 C 26 D D 28 C 29 A A 30 D A 31 B B 32 B C 33 B D 34 B B C B 二、填空题

1．[1] ____ x>=0_______ [2] ____ x=`0`&&c<=`9`__ 3．[1] ______ x1 ______ [2] ______ x1/2-2_______ 4．[1] __ r=m；m=n；n=r；[2] ____ m%n ________ _____ 5．[1] __ i%3==2&&i%5==3&&i%7==2 _[2] ____ j%5==0____ 6．[1] _____ n ______ [2] _____ max=t ____ 7． [1] _______ i

15