Java面试题集(最全版)(4)

2019-02-17 15:12

4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. 26. 27. 28. 29. 30. 31. 32. 33. 34. 35. 36. 37. 38. 39. 40. 41. 42. 43. 44. 45. 46. 47.

private String strNumChFormat;

private String strNumTemp;

private int intNumLen;

private String strBegin;

public Reader(String strNum) { this.strNum = strNum; }

public boolean check(String strNum) { boolean valid = false;

if (strNum.substring(0, 1).equals(\ this.strNum = strNum.substring(1); }

try {

new Double(strNum); valid = true;

} catch (NumberFormatException ex) {

System.out.println(\ }

return valid; }

public void init() { strNumChFormat = \

intNumLen = strNum.length(); strNumTemp = strNum;

strNumTemp = strNumTemp.replace('1', '一'); strNumTemp = strNumTemp.replace('2', '二'); strNumTemp = strNumTemp.replace('3', '三'); strNumTemp = strNumTemp.replace('4', '四'); strNumTemp = strNumTemp.replace('5', '五'); strNumTemp = strNumTemp.replace('6', '六'); strNumTemp = strNumTemp.replace('7', '七'); strNumTemp = strNumTemp.replace('8', '八'); strNumTemp = strNumTemp.replace('9', '九'); strNumTemp = strNumTemp.replace('0', '零'); strNumTemp = strNumTemp.replace('.', '点'); strBegin = strNumTemp.substring(0, 1); }

?Copyleft;2008-10-01; by feeling. 16

48. 49. 50. 51. 52. public String readNum() { if (check(strNum)) { init(); try {

for (int i = 1, j = 1, k = 1; i < intNumLen; i++) {

53. if (strNumTemp.charAt(intNumLen - 1) == '' && i == 1) {

54. strNumChFormat = \位\

55. } else if (strNumTemp.charAt(intNumLen - i) == '' && j == 1) {

56. strNumChFormat = \位\

57. } else if (strNumTemp.charAt(intNumLen - i) == '点') {

58. j = 1; 59. k = 1;

60. strNumChFormat = strNumTemp.charAt(intNumLen - i) + strNumChFormat;

61. continue; 62. } else {

63. strNumChFormat = strNumTemp.charAt(intNumLen - i) + strNumChFormat;

64. } 65. if (strNumTemp.charAt(intNumLen - i - 1) != '' && strNumTemp.charAt(intNumLen - i - 1) != '零') {

66. if (j == 1 && i < intNumLen) {

67. 68. 69. 70. 71. 72. 73. 74. 75. 76. 77. 78. 79. 80. 81. 82. 83. 84. 85.

strNumChFormat = '拾' + strNumChFormat; } else if (j == 2 && i < intNumLen) { strNumChFormat = '百' + strNumChFormat; } else if (j == 3 && i < intNumLen) { strNumChFormat = '千' + strNumChFormat; } }

if (j == 4 && i < intNumLen) { j = 0; }

if (k == 4 && i < intNumLen) {

strNumChFormat = '万' + strNumChFormat; } else if (k == 8 && i < intNumLen) { k = 0;

strNumChFormat = '亿' + strNumChFormat; } j++; k++; }

?Copyleft;2008-10-01; by feeling. 17

86. while (strNumChFormat.indexOf(\位\87. strNumChFormat = strNumChFormat.replaceAll(\\

88. }

89. if (strNumChFormat.substring(0, 2) == \一拾\

90. strNumChFormat = strNumChFormat.substring(1, strNumChFormat.length());

91. }

92. 93.

if (strNumChFormat.indexOf(\点\

String rebegin = strNumChFormat.substring(0, strNumChF

ormat.indexOf(\点\

94. String relast = strNumChFormat.substring(strNumChFormat.indexOf(\点\

95. for (int i = 1; i <= relast.length(); i++) {

96. 97. 98. 99. 100. 101. 102. 103. 104. 105. 106. 107. 108.

relast = relast.replaceAll(\拾\ relast = relast.replaceAll(\百\ relast = relast.replaceAll(\千\ relast = relast.replaceAll(\万\ relast = relast.replaceAll(\亿\ }

strNumChFormat = rebegin + relast; }

} catch (ArrayIndexOutOfBoundsException ex) { ex.printStackTrace(); } catch (Exception ex) { ex.printStackTrace(); }

109. int off = strNumChFormat.indexOf(\点\

110. strNumChFormat = strBegin + strNumChFormat.substring(0);

111. 112. 113. 114. 115. 116. 117. 118. 119. 120. 121. 122.

123. } catch (Exception ex) {

} else {

strNumChFormat = \ }

return strNumChFormat; }

public static void main(String args[]) { try {

String number = args[0].toString();

System.out.println(\ Reader reader = new Reader(number);

System.out.println(\

?Copyleft;2008-10-01; by feeling. 18

124. System.out.println(\number>\

125. } 126. } 127. } 3.现在输入n个数字,以逗号,分开;然后可选择升或者降序排序;按提交键就在另一页面显示按什么排序,结果为,提供reset

import java.util.*;

public class bycomma{

public static String[] splitStringByComma(String source){ if(source==null||source.trim().equals(\ return null;

StringTokenizer commaToker = new StringTokenizer(source,\ String[] result = new String[commaToker.countTokens()]; int i=0;

while(commaToker.hasMoreTokens()){ result[i] = commaToker.nextToken(); i++; }

return result; }

public static void main(String args[]){

String[] s = splitStringByComma(\ int[] ii = new int[s.length]; for(int i = 0;i

Arrays.sort(ii); //asc

for(int i=0;i

for(int i=(s.length-1);i>=0;i--){ System.out.println(ii[i]); } } }

4、金额转换,阿拉伯数字的金额转换成中国传统的形式如:(¥1011)->(一千零一拾一元整)输出。

package test.format;

?Copyleft;2008-10-01; by feeling.

19

import java.text.NumberFormat; import java.util.HashMap;

public class SimpleMoneyFormat { public static final String EMPTY = \ public static final String ZERO = \零\ public static final String ONE = \壹\ public static final String TWO = \贰\ public static final String THREE = \叁\ public static final String FOUR = \肆\ public static final String FIVE = \伍\ public static final String SIX = \陆\ public static final String SEVEN = \柒\ public static final String EIGHT = \捌\ public static final String NINE = \玖\ public static final String TEN = \拾\

public static final String HUNDRED = \佰\ public static final String THOUSAND = \仟\

public static final String TEN_THOUSAND = \万\ public static final String HUNDRED_MILLION = \亿\ public static final String YUAN = \元\ public static final String JIAO = \角\ public static final String FEN = \分\ public static final String DOT = \

private static SimpleMoneyFormat formatter = null;

private HashMap chineseNumberMap = new HashMap(); private HashMap chineseMoneyPattern = new HashMap();

private NumberFormat numberFormat = NumberFormat.getInstance();

private SimpleMoneyFormat() {

numberFormat.setMaximumFractionDigits(4); numberFormat.setMinimumFractionDigits(2); numberFormat.setGroupingUsed(false);

chineseNumberMap.put(\ chineseNumberMap.put(\ chineseNumberMap.put(\ chineseNumberMap.put(\ chineseNumberMap.put(\ chineseNumberMap.put(\ chineseNumberMap.put(\ chineseNumberMap.put(\ chineseNumberMap.put(\ chineseNumberMap.put(\

?Copyleft;2008-10-01; by feeling.

20


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