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22解：（1）由Sn?2an?2?知????????????????????????Sn?1?2an?1?2??????2分??????????????????????Sn?Sn?1?2?an?an?1??an????????????????????即??an?2an?1???????????????????????4分????????????????????而???S1?2a1?2???????????????????????????a1?2??????????????????????数列?an?为等比数列,且an?2n??????6分ˊ????????????（2）由（1）可得???bn?log2an?n??????????????????????cn??????????????????????Tn?bnn?n?????????????????????8分??an2123n?2?3???n??????22221123n?????????????????????Tn?2?3?4???n?1???????10分??222221?1?111?n??????????????????????Tn?Tn????2?3???n??n?12?2?222?2?11n????????????????????Tn?1?n?n?1???????????????????????12分
2221n????????????????????Tn?2?n?1?n?2??????????????14分22
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