A 装箱问题模拟(20)
源码:
#include
char box[1010];
int main() {
memset(box,100,sizeof(box)); int N; int t;
int num=0; cin>>N;
int temp = N; while(temp--) {
cin>>t;
for (int i=0;i int a = box[i]; if (a>=t) { if (a==100) num++; box[i] -=t; cout< cout< //system(\ return 0; } B 表达式转换(25) 源码: #include stack int main() { string s; string anwser; cin>>s; int i; bool number = false; bool firstFlag = true; string snum = \ for(i = 0; i < s.length(); ++i) { if(s[i] >= '0' && s[i] <= '9' || s[i] == '.') { number = true; snum += s[i]; } else if(number == true) { number = false; if(firstFlag) firstFlag = false; else anwser += \ if(snum[0] == '+') snum.erase(snum.begin()); anwser += snum; snum = \ } if(s[i] == '+' || s[i] == '-') { if(i == 0 || s[i-1] == '+' || s[i-1] == '-' || s[i-1] == '*' || s[i-1] == '/' || s[i-1] == '(' ) snum += s[i]; else { while(sta.size() && sta.top() != '(') { int t = sta.top(); if(firstFlag) firstFlag = false; else anwser += \ anwser += t; sta.pop(); } sta.push(s[i]); } } else if(s[i] == '*' || s[i] == '/') { while(sta.size() && sta.top() != '(') { int t = sta.top(); if(t == '-' || t == '+') break; if(firstFlag) firstFlag = false; else anwser += \ anwser += sta.top(); sta.pop(); } sta.push(s[i]); } else if(s[i] == ')') { while(sta.size() && sta.top() != '(') { if(firstFlag) firstFlag = false; else anwser += \ anwser += sta.top(); sta.pop(); } if(sta.size()) sta.pop(); } else if(s[i] == '(') sta.push(s[i]); } if(snum != \ { if(firstFlag) firstFlag = false; else anwser += \ anwser += snum; } while(sta.size()) { if(firstFlag) firstFlag = false; else anwser += \ anwser += sta.top(); sta.pop(); } cout< C 家谱处理(30) 源码: #include struct Person { string name; int level; }; int main() { // freopen(\ ios_base::sync_with_stdio(0); // cin.tie(0); vector if(cin.get()!='\\n') cin.unget(); int s_cnt=0; while(cin.get()==' ') ++s_cnt; cin.unget(); Person pe_tmp; pe_tmp.level=s_cnt; cin>>pe_tmp.name; family_tree.push_back(pe_tmp); } // for(vector it=family_tree.begin();it!=family_tree.end();++it) // { // cout< string name_a,name_b,relation; while(m--) { cin>>name_a; int count=6; while(count--) cin.get(); char ch; cin.get(ch); if(ch=='c'||ch=='e') { relation=\ } else if(ch=='s') relation=\ else { relation=\ } cin.ignore(256,'f');