c答案(8)

{for(i=0;i

{if(str[i]!='\\0')

if(str[i]>='a'&&str[i]<'z'||str[i]>='A'&&str[i]<'Z') str[i]++;

else if(str[i]=='z'||str[i]=='Z') str[i]-=25; } } #endif

printf(\}

第九章 指针 9.1

main()

{int n1,n2,n3;

int *p1,*p2,*p3;

scanf(\ p1=&n1; p2=&n2; p3=&n3; if(n1>n2)swap(p1,p2); if(n1>n3)swap(p1,p3); if(n2>n3)swap(p2,p3);

printf(\

}

swap(p1,p2)

int *p1,*p2; {int p;

p=*p1;*p1=*p2;*p2=p; } 9.2 main()

{char *str1[20],*str2[20],*str3[20]; char swap(); scanf(\ scanf(\ scanf(\

if(strcmp(str1,str2)>0)swap(str1,str2); if(strcmp(str1,str3)>0)swap(str1,str3); if(strcmp(str2,str3)>0)swap(str2,str3); printf(\}

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char swap(p1,p2) char *p1,*p2; {char *p[20]; strcpy(p,p1); strcpy(p1,p2); strcpy(p2,p); } 9.3 main()

{int number[10]; input(number);

max_min_value(number); output(number); }

input(number) int number[10]; {int i;

for(i=0;i<10;i++)

scanf(\}

max_min_value(number) int number[10]; {int *max,*min; int *p,*end; end=number+10; max=min=number;

for(p=number+1;p*max)max=p; else if(*p<*min)min=p; *p=number[0]; number[0]=*min; *min=*p;

*p=number[9]; number[9]=*max; *max=*p; return; }

output(number) int number[10]; {int *p;

for(p=number;p

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}

9.4 main()

{int number[20],n,m,i; scanf(\ scanf(\

for(i=0;i

scanf(\ move(number,n,m); for(i=0;i

printf(\}

move(array,n,m) int array[20],n,m; {int *p,end;

end=*(array+n-1);

for(p=array+n-1;p>array;p--) *p=*(p-1); *array=end; m--;

if(m>0)move(array,n,m); } 9.5

#define nmax 50 main()

{int i,k,m,n,num[nmax],*p; scanf(\ p=num; for(i=0;i

if(i==n)i=0; }

while(*p==0)p++;

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printf(\} 9.6 main() {int len; char *str[20]; scanf(\ len=length(str); printf(\}

length(p) char *p; {int n=0; while(*p!='\\0') {n++;p++;} return(n); } 9.7 main()

{int m;

char *str1[20],*str2[20]; scanf(\ scanf(\ if(strlen(str1)

{copystr(str1,str2,m); printf(\ } }

copystr(p1,p

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