概率论答案(3)

2019-04-04 22:54

(B)

1.随机变量X与Y均服从正态分布。X~N(μ,42),Y~N(μ,52),证P1=P?X???4?,P2=P?Y???5?,则() (A)对任何实数μ,都有P1?P2 (B)对任何实数μ,都有P1?P2 (C)只对μ的个别值,才有P1=P2 (D)对任何实数μ,都有P1>P2

?X???解:p1?P?X???4??P???1?????1??4??Y????Y???p2?P?Y???5??P??1?1?P??1??1???1?

?5??5?????X??1???X?????1??1???1?即P1?P2故(A)成立。

2.设随机变量X~N(μ,?2),则随着?的增大,概率P?X?????()

(A)单调增大(B)单调减小(C)保持不变(D)增减不定 解:?X~N(μ,?2)

?X???~N(0,1)

?X??? ?P?X??????P??1????1?????1??2??1??1?故(C)成立。???

3.设F1(x)与F2(x)分别为随机变量X1与X2的分布函数,为使F(x)=aF1(x)-bF2(x)是某随机变量的分布函数,在下列给定的各组数值中应取() (A)a=35,b=-25

(B)a=23,b=23 (C)a=-12,b=32 (D)a=12,b=-32

解:?F1?x?,F2?x?都是分布函数,?F1?????1,F2?????1为使F?x??aF函数,必满足条件:F?????1 1?x??bF2?x?是某一随机变量的分布即:a?b?1故(A)成立 (C)计算题

1.设测量误差X~N(0,102),试求在100次独立重复测量中,至少有三次测量误差的绝对值大于19.6的概率α,并用泊松分布求出α的近似值(要求小数点后取两位有效数字). λ e??1 2 3 4 5 6 7 0.368 0.135 0.050 0.018 0.007 0.002 0.001

解:设100次独立重复测量中有Y次测量误差的绝对值大于19.6,则Y~B(100,p),p=P?X?X~N(0,1) 10?19.6?

?X??X??p?P?X?19.6??P??1.96??1?P??1.96??2?1???1.96???2(1?0.975)?0.05?10??10?012??P?Y?3??1??P?Y?i??1?(C100?0.050?0.95100?C100?0.051?0.9599?C100?0.052?0.9598)i?02100?99?0.052?0.9598)?0.8817370192若用泊松分布求?的近似值,因??100?0.05?5则有?1?(0.95100?5?0.9599?50?551?552?5??1?e?e?e?1?18.5e?5?1?18.5?0.007?0.87

0!1!2!

2.一实习生用同一台机器接连独立地加工3个同种零件,第i个零是不合格品的概率Pi?1,(i=1,2,3,),此 X 表示1?i3个

零件中合格品的个数,求P{X=2}.

解:令Ai?“加工的第i个零件是合格品”(i?1,2,3)由题意A1,A2,A3相互独立,且P(Ai)?1??“X?2”?A1A2A3?A1A2A3?A1A2A312111312311?P?X?2??P(A1A2A3)?P(A1A2A3)?P(A1A2A3)??????????234234234241i?(i?1,2,3)1?i1?i

3.设随机变量X的绝对值不大于1,P{X=-1}=1,P{X=1}=1.在

84事件{-1

率与该子区间的长度成正比,求:

(1)X的分布函数F(x)=P{X≤x};(2)X取负值的概率

115解:P?X?1??0,P?X?1??1,P?X?1??1?P?X?1??1???848对任意的(c,d)?(?1,1)有PX?(c,d)X?1?k(d?c),其中k为比例系数,??特别地,取(c,d)?(?1,1)得1?PX?(?1,1)x?1?k?1???1???2k?k?12(1)当x??1时,F(x)?0,当x?1时,F(x)?1.故可设定?1?x?1,由全概率公式??P?X?x??P?X?x,X?1??P?X?x,X?1??P?X?x,X??1??P?X?x,X?1?5x???1?1?P?X?x,X?1??P?X?x,X??1??P?X?1?P()X?xX?1?P?X??1????828?0x??1?1故F(x)???5?x?1??2?,?1?x?1?16x?11?7(2)?F(x)在(?1,1)内是连续的,?P?X?0??F(0?0)?F(0)?16??


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