acm日期比较代码实现(2)

11 11 1111 12 12 1212

Sample Output

01 01 1999 is earlier than 02 02 1999 11 11 1111 is earlier than 12 12 1212

解：

#if !defined __DAY__h__ #define __DAY__h__ #include using std::istream; using std::ostream; class Day { }; #endif

#include\#include #include using namespace std;

Day::Day(int a, int b, int c) { }

int Day::Break(void) { }

istream &operator>>(istream &input,Day &s)

if(day==0&&mon==0&&year==0)

return 0; else return 1; mon=a; day=b; year=c;

friend istream & operator>>(istream &input,Day &s); friend ostream & operator<<(ostream &output,Day &s); Day(int a=0,int b=0,int c=0); int Break(void); int operator<(Day &s); int day; int mon; int year;

public:

private:

{ }

ostream &operator<<(ostream &output,Day &s) { }

int Day::operator<(Day &s) {

if(s.mon>12||s.mon<=0) { }

else if(s.day>31) { } else { }

else if((s.year%4==0||(s.year0!=0&&s.year@0==0))&&s.day>29&&s.mon==2) { }

else if((!(s.year%4==0||(s.year0!=0&&s.year@0==0)))&&s.day>28&&s.mon==2) { }

if(mon>12||mon<=0) { }

cout<<\您输入的月份错误!\<

cout<<\您输入的日期错误!\<

cout<<\您输入的日期错误!\<

cout<<\您输入的日期错误!\<

cout<<\您输入的日期错误!\<

cout<<\您输入的月份错误!\<

output<

input>>s.mon>>s.day>>s.year; return input;

\<

if((s.mon==1||s.mon==3||s.mon==5||s.mon==7||s.mon==8||s.mon==10||s.mon==12)&&s.day>31)

}

else if(day>31) { }

else if((mon==1||mon==3||mon==5||mon==7||mon==8||mon==10||mon==12)&&day>31) { } { }

if((!(year%4==0||(year0!=0&&year@0==0)))&&day>28&&mon==2) { }

if(years.year)return 0; else { }

if(mons.mon) return 0; else { }

if(days.day) return 0; else return -1;

cout<<\您输入的日期错误!\<

cout<<\您输入的日期错误!\<

else if((year%4==0||(year0!=0&&year@0==0))&&day>29&&mon==2)

cout<<\您输入的日期错误!\<

cout<<\您输入的日期错误!\<

#include #include%using namespace std; int main() {

Day a,b;

cout<<\若要退出请输入:\\n0 0 0\<

cout<<\请输入要进行比较的两个具体的日期(格式为:mon day year):\<

}

cin>>a>>b;

while(a.Break()!=0) { } return 0;

re=a

if(re==1) { }

if(re==-1) { }

cin>>a>>b;

cout<