C语言程序设计实验报告9(2)

else {

loc_head = (struct s_list *)malloc(sizeof(struct s_list)); loc_head -> data = *p++; tail = loc_head; while(*p){

temp = (struct s_list *)malloc(sizeof(struct s_list)); temp -> next = loc_head; loc_head = temp;

loc_head -> data = *p++; }

tail -> next = NULL; }

*headp = loc_head; }

程序运行结果如下：

3.程序设计的实验步骤及结果 （1）

1)创建一个工程

建立名为prj2的工程。 2)编辑源文件和保存 程序如下

#include struct bits{

unsigned char bit0:1, bit1:1, bit2:1, bit3:1, bit4:1, bit5:1, bit6:1, bit7:1; }a;

union w{

unsigned char t; struct bits a; }m;

void f0(struct bits b) {

printf(\}

void f1(struct bits b) {

printf(\}

void f2(struct bits b) {

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printf(\}

void f3(struct bits b) {

printf(\}

void f4(struct bits b) {

printf(\}

void f5(struct bits b) {

printf(\}

void f6(struct bits b) {

printf(\}

void f7(struct bits b) {

printf(\}

void main() {

unsigned int n;

void (*p_fun[8])(struct bits b); printf(\ scanf(\ m.t = n;

m.a.bit0 = 1; p_fun[0] = f0; p_fun[1] = f1; p_fun[2] = f2; p_fun[3] = f3; p_fun[4] = f4; p_fun[5] = f5; p_fun[6] = f6; p_fun[7] = f7; if(m.a.bit0)

p_fun[0](m.a); if(m.a.bit1)

p_fun[1](m.a); if(m.a.bit2)

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p_fun[2](m.a); if(m.a.bit3)

p_fun[3](m.a); if(m.a.bit4)

p_fun[4](m.a); if(m.a.bit5)

p_fun[5](m.a); if(m.a.bit6)

p_fun[6](m.a); if(m.a.bit7)

p_fun[7](m.a); }

运行结果如下所示：

结果正确！ （2）

1)创建一个工程

建立名为prj3工程。 2)编辑源文件和保存 程序如下

#include #include #include struct list{

char num[8]; char name[9]; int english; int math; int phy; int c;

struct list *next; }*p, *q;

struct list *creat_list(int n) {

int i;

struct list *head = NULL;

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for(i = 0; i < n; i++) {

p = (struct list *)malloc(sizeof(struct list)); if(i == 0)

head = p; else

q -> next = p; printf(\

scanf(\ printf(\

scanf(\

printf(\

scanf(\ printf(\ q = p;

p -> next = NULL; }

return head; }

void output(struct list *head, int n) {

printf(\ name english math phy c\\n\ for (p = head; n > 0; n--, p = p -> next) {

printf(\-> math, p -> phy, p -> c); } }

void xiugai(struct list *head) {

char a[8]; int s;

int k, i, m;

printf(\您想修改第几个学生的信息？\\n\ scanf(\

for(q = head, i = 0; i < k - 1; i++) q = q -> next;

printf(\您想修改哪项信息？\\n\

printf(\ scanf(\ switch(m) {

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case 1:

printf(\输入新学号：\ scanf(\

strcpy(q -> num, a);

printf(\确认新学号：%s\ break; case 2:

printf(\输入新姓名：\ scanf(\

strcpy(q -> name, a);

printf(\确认新姓名：%s\ break; case 3:

printf(\输入新英语成绩：\ scanf(\ q -> english = s;

printf(\确认新英语成绩：%d\ break; case 4:

printf(\输入新数学成绩：\ scanf(\ q -> math = s;

printf(\确认新数学成绩：%d\ break; case 5:

printf(\输入新物理成绩：\ scanf(\ q -> phy = s;

printf(\确认新物理成绩：%d\ break; case 6:

printf(\输入新c成绩：\ scanf(\ q -> c = s;

printf(\确认新c成绩：%d\ break; default:

printf(\ }

printf(\}

void aver(struct list *head, int n) {

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