2． 滤池(包括管廊)底板计算： (1) 滤池底板板底应力计算：（底板取600厚） P1 = 34.48x4.3x0.35x2.5+1.65x0.9x34.48+1.78x0.45x34.48 = 129.731+51.2+27.62= 208.62 t P2 = 1.65x2.68x0.25x2.5x13 = 35.93 t P3 = 34.48x2.68x0.25x2.5+1.65x0.9x34.48+1.5x1.12x34.48+0.5x1.78x0.45x34.48 +34.48x1.42x0.1x2.5 = 166.884+13.81+12.24 = 192.94 t P4 = 32x3.7x0.35x2.5+1.5x1.12x34.480.5x1.78x0.45x34.48+34.48x1.42x0.1x2.5 = 103.6+57.93+13.81+12.24 = 187.58 t P5 = 32x6.88x0.35x2.5+0.5x0.7x11.98x2.5x5+0.5x5.8x2x34.48x1+0.53x2.5x32
+0.8x0.4x2.5x32x2+0.35x0.4x2.5x2.2x5x2+0.25x0.4x2.5x2.55x8x2 = 192.64+52.42+199.984+42.4+51.2+7.7+10.2 = 556.544 t P6 = 7.2x2.9x0.2x2.5x4+2x2.35x0.2x2.5x4+34.48x1.5x0.3x2.5 = 41.76+9.4+38.8 = 90 t P7 = 4.1x0.3x34.48x2.5+1.4x0.53x34.48+1.23x34.48x0.4 = 106.03+25.6+17 = 148.63 t P8 = 32x6.88x0.4x2.5+0.5x0.7x11.98x2.5x5+0.5x5.8x2x34.48x1+0.53x2.5x32+0.8x
0.4x2.5x32x2+1.23x34.48x0.4+0.35x0.4x2.5x2.2x5x2+0.25x0.4x2.5x2.55x8x2 = 220.16+52.42+199.984+42.4+51.2+17+7.7+10.2
= 601.06 t P9 = 1.18x (0.3x1.42x2.5x2+0.35x1.42x2.5x2+0.45x1.2x2+0.05x1.2x4)=7 t P10= 0.95x0.3x34.48=9.83 t
q = 4.14x (0.35+0.35+0.3+0.3+0.3) x2.5+(0.30+0.15+0.07)x1.2x2+0.8 = 16.56+1.25+0.8=18.61 t/m
Pq = 18.61x15=279.15 t P(土1) = 20.375x4.28=62.725 t P(土2) = 6.5x9.65=87.21 t Pdb = 26.5x51.72=1370.58 t
每格滤池工作时滤料加水重： P(滤料+水) = 15x8x(0.65x1.95+3.8x1)= 608.1 t
滤池四格均正常工作时：
∑G = 208.62+35.93+192.94+187.58+556.544+90+148.63+601.06+287.045+7+9.83 +273.15+62.725+87.21+1370.58+608.1x4
= 4111.85 + 2432.67 = 6544.25 t
对底板边缘弯矩： M = 208.62x0.675+35.93x1.675+192.94x2.63+187.58x5.03+556.544x20.38+90x21.85
+148.63x23.55+601.06x25.8+7x4.437+21.025x9.83
+ 279.15x12.7+24x6.79+38.713x10.1875+87.21x23.25+1370.58x13.25 +608.1x4x12.7
= 140.82+60.183+507.43+943.53+11342.367+1966.5+3500.24+15507.35 +31.06+206.676+3545.21+162.96+394.4+2027.633+18160.185+30891.48 = 89388.024 tm
X = 13.66 m (往右偏离底板中心线0.41m) 对底板中心线弯矩：
∑M = 0.41x6544.25 = 2683.1425 tm
Wx = 34.48x26.52/6 = 4035.6 m3
∑M / W = 2683.1425/4035.6 = 0.665 t/m2 底板面积：
S = 26.5x34.48 = 913.72 m2 底板下地基附加应力：
Qmax = (∑G/S)+(∑M / W) = 7.163+0.665 = 7.83 t/m2 Qmin = (∑G/S)-(∑M / W) = 7.163-0.665 = 6.5 t/m2
最不利工况(滤池三格正常工作,最外格空池检修时)：
∑G = 208.62+35.93+192.94+187.58+556.544+90+148.63+601.06+287.045+7+9.83 +273.15+62.725+87.21+1370.58+608.1x3
= 4111.85 + 1824.3 = 5936.15 t 对底板边缘弯矩: M = 208.62x0.675+35.93x1.675+192.94x2.63+187.58x5.03+556.544x20.38+90x21.85
+148.63x23.55+601.06x25.8+7x4.437+21.025x9.83
+ 279.15x12.7+24x6.79+38.713x10.1875+87.21x23.25+1370.58x13.25
+608.1x4x12.7
= 140.82+60.183+507.43+943.53+11342.367+1966.5+3500.24+15507.35 +31.06+206.676+3545.21+162.96+394.4+2027.633+18160.185+23168.61 = 81665.154 tm
X = 13.76 m (距底板中心线0.51m 右) 对底板中心线弯矩：
∑M = 0.51x5936.15 = 3027.44 tm Wx = 34.48x26.52/6 = 4035.6 m3 ∑M / W = 3027.44/4035.6 = 0.75 t/m2 底板下地基附加应力： Qmax = (∑G/S)+(∑M / W) = 6.5+0.75 = 7.25 t/m2 Qmin = (∑G/S)-(∑M / W) = 6.5-0.75 = 5.75 t/m2 底板下地基附加应力分布如下图：(纵向) 滤池区地基附加应力计算： Qmax = 6.9 t/m2 Qmin = 6.03 t/m2 滤池区平均地基附加应力：QLC = (6.03+6.9)/2 = 6.465 (实取：qL = 6.5 t/m2) 计入横向偏心时滤池区地基附加应力计算： ∑G = 5936.15 t ∑M = 608.1x3x4.94 = 9012.042 tm Wy = 26.5x34.482/6 = 5250.844 m3 ∑M / W = 9012.042/5250.844 = 1.7163 t/m2 底板下地基附加应力： Qmax = QLC+(∑M / W) = 6.5+1.72 = 8.22 t/m2 Qmin = QLC-(∑M / W) = 6.5-1.72 = 4.78 t/m2 底板下地基附加应力分布如下图： 底板受地基净反力分布如下图： 最外格滤池底板受平均净反力：q = (3.34+4.1)/2 = 3.72 t/m2 实取q = 4 t/m (2) 滤池底板内力计算： 2q = 4 t/mLx/Ly = 8.35/15.35= 0.544
Mx_max = [0.0965+(1/6)×0.0174]×4×8.352
= 27.722 tm 2 壁板厚取：600mm，保护层厚：30mm，混凝土强度等级为：C25， X方向上层通长配筋为：Φ22@100 [28.34 tm] My_max = [0.021+(1/6)×0.0892]×2×8.352 = 10 tm 壁板厚取：600mm，保护层厚：30mm，混凝土强度等级为：C25， Y方向上层通长配筋为：Φ18@200 [12.36 tm] q= 4 t/m2
Lx/Ly=8.35/15.35=0.544
Mx_max = [0.0646+(1/6)×0.0063]×4×8.352 = 20.95 tm 壁板厚取：600mm，保护层厚：30mm，混凝土强度等级为：C25， X方向通长配筋为：Φ18@100 [21.12 tm] My_max = [0.0087+(1/6)×0.0618]×4×8.352 = 5.3 tm 壁板厚取：600mm，保护层厚：30mm，混凝土强度等级为：C25， Y方向通长配筋为：Φ16@200 [12.14 tm] Mox = 0.1212×4×8.352 = 33.80 tm 壁板厚取：600mm，保护层厚：35mm，混凝土强度等级为：C25， X方向下层支座配筋为：Φ25@100 [38.20 tm]
q= 4 t/m2