C++复习题(2015)(5)

{

public:

B(){cout<<\ ~B(){cout<<\ }; void main() {

B b; }

结果：1342

8.＃include void mian() {

int n=10; int* pn=&n; int* &rn=pn; (*pn)++;

cout<<\ (*rn)++;

cout<<”n=”< void main()

{ int n=0,j=0,s=0;

for (int i=8;i<=20;i++) { n++;i++; if (i%4==0) j++; else s++;

} cout<<\}

10. #include

void fun(int i); void main( ) { int n;

for (n=1;n<5;n++) fun(n); }

void fun(int i ) { static s=0; s+=i;

cout<

}

11. #include

void main()

{ int i,a[]={1,2,3,4,5,6,7,8},*p=a; for (i=1;i<5;i++)

p[i]=a[i-1]+a[i+1]; cout<

}

12. class mystr

{ char string[81];int len; public:

mystr(char *s){strcpy(string,s);}

void getvalue(char *s,int &n)

{strcpy(s,string); n=len; }

friend mystr operator+(mystr a,mystr b) {mystr c(\

strcpy(c.string,a.string); strcat(c.string,b.string); c.len=strlen(c.string); return c;} };

void main()

{ char st[81]; int l;

mystr a(\ c=a+b;

c.getvalue(st,l);

cout << st<

13. #include

#include int count=0; class Point{ int x,y; public:

Point(){x=1;y=1;count++;} ~Point(){count--;} friend void display(); };

void display()

{cout <<\void main() { Point a; display(); { Point b[5]; display(); }

display(); }

14．#include

class base { public:

virtual void show()

{cout<<\};

class derived:public base {public:

void show()

{cout<<\};

void display(base *obj) {obj->show();} void main() { base demo1; derived demo2; display(&demo1); display(&demo2); }

9-14运行结果： 9.n=7 i=22 s=7 10.1 3 6 10 11.13

12.Hello everybody! Len=16

13.There are 1points,

There are 6points, There are 1points,

14.class base show() is called. class derived show() is called. 15．阅读以下程序，写出输出结果。

#include

using namespace std; int main()

{ int a = 0, b = 1;

switch( a )

{ case 0: switch( b )

{ case 0 : cout<<\ case 1 : cout<<\ }

case 1: a++; b++; cout<<\ } } 【解答】 a=0 b=1 a=1 b=2

16．阅读以下程序，写出输出结果。

#include using namespace std; int main() { int i = 1; while( i<=10 ) if( ++i % 3 != 1 ) continue;

else cout << i << endl; } 【解答】

4 7 10

17．阅读以下程序，写出输出结果。

#include using namespace std; class T { public :

T( int x, int y ) { a = x ; b = y ;

cout << \调用构造函数.\ cout << a << '\\t' << b << endl ;

} T( T &d )

{ cout << \调用构造函数.\ cout << d.a << '\\t' << d.b << endl ; }

~T() { cout << \调用析构函数.\ int add( int x, int y = 10 ) { return x + y ; } private : int a, b ; };

int main() { T d1( 4, 8 ) ; T d2( d1 ) ;

cout << d2.add( 10 ) << endl ; } 【解答】

调用构造函数1. 4 8 调用构造函数2. 4 8 20

调用析构函数. 调用析构函数.

18.阅读以下程序，写出输出结果。

#include using namespace std; int main() { int a=10, b=20;

int *p = &a, *q = &b; *p = *p * *q; int & ra = a; ra=a;

int * & rt = q; *rt = 30;