区域电力网规划设计(9)

2019-08-30 12:13

~SA1=90.38+j51.4+1.79+j5.85=92.17+j57.25(MVA)

从发电厂A算变电站1上的压降:

??PX?QR?PR?QX?U1=?UA?????UUA?A???22

2=92.17?8?57.25?26.2???92.17?26.2?57.25?8?242??????242242????2 =232.9(kV)

6.2 正常运行时最小负荷情况

首先算出各变电站的负荷损耗,得到各节点的最大潮流分布。 由SSPL1-90000/220变压器的参数:

I0%?0.67

5 P0?92kW UK%?13.7 PK?472.kW

可得:RT?PKUN221000SN?472.5????1000?902??2.82?

XT?UK%UN100SN2?????????100?90??73.68?

GT?P01000UNI0%SN100UN22?921000???00.67?902?1.9?10?6S

BT??100???02?1.25?10?5S

变电站1: 两台变压器并联,RT?1.41?,XT?36.84?,GT?3.8?10?6S,BT?2.5?10?5S 变压器损耗为:

~?SZT=

P?QUN222?R?jX?=

80?49.6220222?1.41?j36.84?=0.26+j6.74(MVA)

?SYT=GTUN?jBTUN~22=0.09+j0.61(MVA)

运算负荷为:

~~~~S1'?S1??SZT??SYT?80?j49.6?(0.2?j6.74)?(0.09?j0.61)?80.29?j56.95(MVA)

同理变电站2运算负荷为:

~~~~S2'?S2??SZT??SYT?70?j43.4?(0.21?j5.6)?(0.09?j0.61)?70.3?j49.61(MVA)

由SSPSL1-120000/220变压器的参数:

I0%?1.0 PK12?510kW

PK13?165kW PK23?227kW P0?123.1kW

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UK12%?24.7 UK13%?14.7 UK23%?8.8

1?P??k12?510?660?908??131?1? ?Pk2??510?908?660??379

2?1?P??k32?908?660?510??529?1?U%??24.7?29.4?17.6??18.3?k12?1??Uk2%??24.7?17.6?29.4??6.5

2?1?U%??17.6?29.4?24.7??11.2?k32?变电站3:

~?ST31=(2P01000?jI00SN)?2[U%SS22()?jk1?SN?()] 10002SN1002SN13175/0.85218.375/0.852()+j?120?()] 10002?1201002?120Pk1(=2?123.11000+j1.0100?120)+2[=0.25+j2.4+0.04+j5.9=0.29+j8.3(MVA)

~?ST32=(2P01000?jI00SN)?2[U%SS22()?jk2?SN?()] 10002SN1002SN37975/0.8526.575/0.852()+j?120?()] 10002?1201002?120Pk2(=2?123.11000+j1.0100?120)+2[=0.25+j2.4+0.28+j5.7=0.53+j8.1(MVA)

~?ST33=(2P01000?jI00SN)?2[U%SS22()?jk3?SN?()] 10002SN1002SN52975/0.85211.275/0.852()+j?120?()] 10002?1201002?120Pk3(=2?123.11000+j1.0100?120)+2[=0.25+j2.4+0.14+j3.6=0.39+j6(MVA)

~~~~?ST3??ST31??ST32??ST33?1.21?j22.4~(MVA)

S3min=75+j46.5+0.91+j15.15=76.21+j68.9(MVA)

同理可求得: 变电站4:S变电站5:S~~4min=70+j43.4+0.99+j17.4=70.99+j60.8(MVA) =85+j52.7+1.37+j22.2=86.37+j74.9(MVA)

38

5min

其次,先算小环网发电厂B、变电站4、变电站5从无功分点4处打开环网,计算潮流。

66.5+j57.245.5+j21.9~SB4SB5~~SB5~'S54~4.49+j3.644.6+j15.1B24.1+j21.425

?S45=

~P?QUN222?R?jX?=

4.49?3.62202?4.6?j15.1?=0.003+j0.01(MVA)

S54?4.49?j3.6?0.003?j0.01?4.493?j3.61(MVA)

SB5=4.493+j3.61+86.37+j74.9=90.863+j78.51(MVA)

?SB5=

~~?2222P?QUN?22?R?~jX?=

90.863?78.512202?4.1?j21.4?=1.22+j6.3(MVA)

SB5=SB5?SB4=

~~~+?SB5=92.083+j84.81(MVA)

22P?QUN~?R?jX?=

66.5?57.2220222?5.5?j21.9?=0.87+j3.5(MVA)

SB4=?SB4+66.5+j57.2=67.37+j60.7(MVA)

~从发电厂经过变电站5算变电站4上的压降:

??PX?QR?PR?QX?U5=?UB?????UUB?B???22

22=92.083?4.1?84.81?21.4???92.083?21.4?84.81?4.1?242??????242242????

=233.1(kV)

??PX?QR?PR?QX?U4=?U5?????

U5U5????22=4.493?4.6?3.61?15.1???4.493?15.1?3.61?4.6?233.1??????233.1233.1????22 =232.8(kV)

从发电厂B直接算变电站4上的压降:

??PX?QR?PR?QX?U4=?UB?????UBUB????22

39

=67.37?5.5?60.7?21.9???67.37?21.9?60.7?5.5?242??????242242????22

=234.9(kV)

变电站2、发电厂A和发电厂B三个节点为两端供电网,从无功分点2处打开两端供电网,计算潮流。

SA2~~?SA225.74+j18.172A13.9+j45.3

~?SA2=

P?QUN222?R?jX?=

25.74?18.17220222?13.9?j45.3?=0.28+j0.93(MVA)

~SA2=25.74+j18.17+0.28+j0.93=26.02+j19.1(MVA)

从发电厂A算变电站2上的压降:

?U2=??U??PX?QRPR?QX???????UAUA??2A????2

22=26.02?13.9?19.1?45.3???26.02?45.3?19.1?13.9?242??????242242???? =237.2(kV)

从发电厂B直接算变电站2上的压降:

SB2~B?SB244.56+j31.4428+j26.2~

?SB2=

~P?QUN222?R?jX?=

44.56?31.44220222?8?j26.2?=0.49+j1.6(MVA)

~SB2=44.56+j31.44+0.49+j1.6=45.05+j33.04(MVA)

从发电厂B算变电站2上的压降:

??PX?QR?PR?QX?U2=?UB?????UU?B??B?22

2=45.05?8?33.04?26.2???45.05?26.2?33.04?8?242??????242242????2 =237.2(kV) 计算无误。

40

同样方法计算,变电站3、发电厂A和发电厂B为两端供电网,从无功分点处打开环网,计算潮流。

SA3~~?SA327.1+j24.53A11.7+j38.3

?SA3=

~P?QUN222?R?jX?=

27.1?24.5220222?11.7?j38.3?=0.32+j1.06(MVA)

~SA3=27.1+j24.5+0.32+j1.06=27.42+j25.56(MVA)

从发电厂A算变电站3上的压降:

??PX?QR?PR?QX?U3=?UA?????UUA?A???22

22=27.42?11.7?25.56?38.3???27.42?38.3?25.56?11.7?242??????242242???? =237.6(kV)

从发电厂B直接算变电站3上的压降:

SB3~?SB3~49.11+j44.43B6.47+j21.2

?SB3=

~~P?QUN222?R?jX?=

49.11?44.4220222?6.47?j21.2?=0.27+j0.87(MVA)

SB3?49.11?j44.4?0.27?j0.87?49.38?j45.27(MVA)

??PX?QR?PR?QX?U3=?UB?????UU?B??B?22

22=49.38?6.47?45.27?21.2???49.38?21.2?45.27?6.47?242??????242242???? =237.6(kV) 线路A-1段:

SA1~?SA1~80.29+j56.951A8+j26.2

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