信息论与编码陈运主编答案完整版(3)

2020-02-22 12:05

?103 103 103 103 103 103 103 103

+ 8 log 8 + 15 log 15 +

?5

log 5 + 12 log 12 ? 103 103

103 103

103?

103 103 103

= 2.836 bit symbol/ H YZ(

) = ?∑∑ p y z( j

k

)log p y z( j k ) j k

= ??? 20 log 20 + 23 log 23 + 32 log 32 + 28 log 28 ?? ?103 103 103 103 103 103 103 103? 1.977 = bit symbol/

H X YZ( / ) = H XYZ( ) ?H YZ(

(3)

) = 2.836?1.977 = 0.859 bit symbol/

I X YZ( ; ) = H X( ) ?H X YZ( / ) = 0.964?0.859 = 0.159 bit symbol/ 2.15 有两个二元随机变量X和Y,它们的联合概率为

Y X x1 =0 1 /8 3 /8 x 2 =1 3 /8 1 /8 y 1 =0 y =1 2 并定义另一随机变量Z = XY(一般乘积),试计算:

(1) H(X), H(Y), H(Z), H(XZ), H(YZ)和H(XYZ);

(2) H(X/Y), H(Y/X), H(X/Z), H(Z/X), H(Y/Z), H(Z/Y), H(X/YZ), H(Y/XZ)和H(Z/XY);

(3) I(X;Y), I(X;Z), I(Y;Z), I(X;Y/Z), I(Y;Z/X)和I(X;Z/Y)。

解: (1)

p x

p x y p x y p x

·11·

p x y

i

p x y

H X() =?∑ p x( i )log p x( i ) =1 bit symbol/

p y

p x y p x y p y

p x y

j

p x y

H Y( ) =?∑ p y( j )log p y( j ) =1 bit symbol/

Z = XY 的概率分布如下:

?Z ? ??z1 = 0 ??P Z( )??=??? 78 z2 =1?? 18 ???

?7711?

H Z( ) =?∑k2 p z( k ) =???8 log 8+ 8log8??= 0.544 bit symbol/

·12·

p x( 1) = p x z( 1 1)+ p x z( 1 2) p x z( 1 2) = 0 p x z( 1

1

) = p x( 1) = 0.5 p z( 1) =

p x z( 1 1)+ p x z( 2 1)

p z( 2) = p x z( 1 2)+

p x z( 2 2)

H XZ( ) =?

∑∑

i

k

?1133 11?

p x z( ik )log p x z( ik ) =??2log 2 + 8log8+ 8log8??=1.406 bit symbol/

?

·13·

p y( 1) = p y z( 1 1)+ p y z( 1 2) p y z( 1 2) = 0 p y z( 1 1) = p y( 1) = 0.5 p z( 1) = p y z( 1 1)+ p y z( 2 1)

p z( 2) = p y z( 1 2)+ p y z( 2 2)

H YZ(

?1133

) =?k p y z( j k )log p y z( j k ) =??2log 2 + 8log8+

?1

8log18??=1.406 bit symbol/ j ?

p x y z( 1 1 2) = 0 p x y z( 1 2 2) =

∑∑

0 p x y z( 2 1 2) = 0 p x y z( 1 1 1)+ p x y z( 1 1 2) = p x y( 1 1) p x y z( 1 1 1) = p x y( 1 1) =1/8 p x y z( 1 2 1)+ p x y z( 1 1 1) = p x z( 1 1)

p x y z( 2 1 1)+ p x y z( 2 1 2) = p x y( 2 1)

·14·

p x y z( 2 2 1) = 0

p x y z( 2 2 1)+ p x y z( 2 2 2) = p x y( 2 2)

H XYZ( ) =?∑∑∑ p x y z( i

i

j

k

jk

)log2 p x y z( i j

k

)

?11 33 33 11?=??log+ log+ log+ log?=1.811 bit symbol/ ?8 8 8 8 8 8 8 8?

(2)

H XY( ) =?

∑∑

i

j

?1133 33 11?

p x y( ij )log2 p x y( ij ) ==??8log8 + 8log8+ 8log8+ 8log8??=1.811 bit symbol/

?

) = H XY( )?H Y( ) =1.811 1? = 0.811 bit symbol/

H X Y( H Y X( H X Z( H Z X( H Y Z(

/ / / / /

) = H XY(

)?H X( ) =1.811 1? = 0.811 bit symbol/

) = H XZ( )?H Z( ) =1.406?0.544 = 0.862 bit symbol/

) = H XZ( )?H X( ) =1.406? =1 0.406 bit symbol/

) = H YZ(

)?H Z( ) =1.406?0.544 = 0.862 bit symbol/

·15·


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