西工大C语言C++作业答案

2020-02-22 14:32

CH0408.txt

# include void main() {

double r,h,l,s,sq,vq,vz; scanf(\l=2*3.141592653*r; s=3.141592653*r*r; sq=4*3.141592653*r*r; vq=4*3.141592653*r*r*r/3; vz=3.141592653*r*r*h;

printf(\}

CH0505.txt

#include void main() { }

int x,y;

scanf(\if (x>=1) if (x>=10) y=3*x-11; else y=2*x-1; else y=x; printf(\

CH0510.txt

#include void main() {

double x,y; int h=10;

scanf (\

if ((x-2)*(x-2)+(y-2)*(y-2)<=1)

printf (\else

if ((x+2)*(x+2)+(y-2)*(y-2)<=1) printf (\else

if ((x-2)*(x-2)+(y+2)*(y+2)<=1) printf (\else

if ((x+2)*(x+2)+(y+2)*(y+2)<=1) printf (\else printf (\}

CH0603.txt

#include #include void main() {

long int a,n,sum=0,b,i; scanf(\for(i=1;i<=n;i++) {

b=pow(10,i); sum+=b; }

sum=a*sum/9;

printf(\}

CH0607.txt

# include #include void main()

{int n,i,j,t,k;

for(n=2;n<=1000;n++) {

i=1;j=0;t=0;k=0;

for(i=1;i

if(n%i==0) t=t+i; } if(t==n) {

printf(\for(i=1;i

} } } }

if(n%i==0&&i!=1) printf(\else if(n%i==0&&i==1) printf(\

printf(\

CH0611.txt

# include #include void main() {

float a,x,x1,x2=1.0; scanf(\x1=(x2+a/x2)/2;

while(fabs(x2-x1)>=pow(10,-5)) { x2=x1;

x1=(x2+a/x2)/2; } x=x1;

printf(\}

CH0613.txt

#include #include void main()

{double x,x1,x2,x3,fx1,fx2,fx3; scanf(\

fx1=(2*x1*x1*x1-4*x1*x1+3*x1-6); fx2=(2*x2*x2*x2-4*x2*x2+3*x2-6); if(fx1*fx2<0)

{

while(fabs(x1-x2)>=1e-6) {

x3=(x1+x2)/2;

fx3=(2*x3*x3*x3-4*x3*x3+3*x3-6); if(fx3*fx1<0) x2=x3;

else x1=x3; } x=x1;

printf(\} }

CH0615.txt

#include void main() { }

char i,j,k;

for(i='x';i<='z';i++) for(j='x';j<='z';j++) if(i!=j)

for(k='x';k<='z';k++)

if(i!=k&&j!=k)

if(i!='x'&&k!='x'&&k!='z') printf(\

CH0701.txt

#include void main() { }

int a[101],i,j;

for(i=2;i<101;i++) a[i]=1;

for(i=2;i<=100;i++)

for(j=2;j*i<=100;j++) a[i*j]=0; for(i=2;i<=100;i++) { }

printf(\

if(a[i]==1) printf(\

CH0707.txt

#include void main() {

int n,i,j,a[16][16],m=1,k; while(m==1) {

scanf(\

if((n!=0)&&(n<=15)&&(n%2!=0)) m=0;

}

for(i=1;i<=n;i++)

for(j=1;j<=n;j++) a[i][j]=0; j=n/2+1; a[1][j]=1;

for(k=2;k<=n*n;k++) { i=i-1; } {

for(j=1;j<=n;j++) printf(\printf(\j=j+1;

if((i<1)&&(j>n)) { } else { }

if(i<1) i=n; if(j>n) j=1; i=i+2; j=j-1;

if (a[i][j]==0) a[i][j]=k; else { }

i=i+2; j=j-1; a[i][j]=k;

for (i=1;i<=n;i++)


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