西工大C语言C++作业答案(3)

char str[50],*pstr;

int i,j,k,m,e10,dight,ndight,a[10],*pa; gets(str); pstr=&str[0]; pa=&a[0]; ndight=0; i=0;

j=0;

while(*(pstr+i)!='\\0') { }

if((*(pstr+i)>='0')&&(*(pstr+i)<='9')) j++; else { } i++;

if(j>0) { }

dight=*(pstr+i-1)-48; k=1;

while(k

e10=1;

for(m=1;m<=k;m++) e10=e10*10;

dight=dight+(*(pstr+i-1-k)-48)*e10; k++;

}

*pa=dight; ndight++; pa++; j=0;

if(j>0) {

dight=*(pstr+i-1)-48; k=1;

while(k

e10=1;

for(m=1;m<=k;m++) e10=e10*10;

dight=dight+(*(pstr+i-1-k)-48)*e10;

}

k++;

}

*pa=dight; ndight++; j=0;

printf(\ j=0;

pa=&a[0]; }

CH1112.txt

#include void main() {

struct NUM {struct NUM *up; struct NUM *next; int n;

}num[1000];

struct NUM *p=&num[0],*p2;p->up=NULL; int t;

do

{scanf(\ p->n=t; p->next=p+1; p->next->up=p; p++;

}while(t!=0);p--;

p->up->next=NULL;p=p->up; p2=&num[0];printf(\原始表:\while(p2->next)

printf(\printf(\反转表:\while(p->up)

printf(\for(j=0;j

}

SXC01.txt

# include # include void main() { }

SXC03.txt

#include void main() { }

double a,b,c;

scanf(\if(a>=20)

if(b>2000) c=b+200; else c=b+180; else

if(b>1500) c=b+150; else c=b+120; printf(\double x,y; scanf(\

if(x<0) y=-x; else

if(x<10) y=x*x; else y=sqrt(x);

printf(\

SXC04.txt

#include void main()

{float a,b,c;

scanf(\c= (a+b/60)*30-b*6; if(c>180) c=360-c; printf(\}

SXC05.txt

# include void main() { }

SXD02.txt

#include void main() { }

SXD03.txt

# include # include void main() {

int m,a,b,x,y,i,k;

scanf(\int i;

for(i=100;i<=200;i++) {

if(i%4==2&&i%7==3&&i%9==5) printf(\}

int a,b,x,y,m,n;

scanf (\m=a*y; n=b*x; if (m>n)

printf(\else

if(m

}

if (a>b) x=b,y=a; else x=a,y=b;

for(m=x;m<=y;m=m++) { k=sqrt(m);

for (i=2;i<=k;i++)

if(m%i==0) break; if(i>=k+1)

}

printf(\

SXD04.txt

# include # include void main() { }

SXD06.txt

#include #include void main() {

int i1,i2,i3,i5,i8,ii1,ii2,ii3,ii5,ii8; double max,n;

for(i8=0;i8<=2;i8++){ for(i5=0;i5<=(20-8*i8)/5;i5++){ double s,a,b,c,i; a=2;b=1;s=0;

for(i=1;i<=20;i++) { s=s+a/b; c=a; a=a+b; b=c; }

printf(\