基于matlab的QPSK仿真(5)

2020-04-21 03:40

end;

if (symbolerror==1), numofsymbolerror=numofsymbolerror+1; end; end

counter=counter+1; end

ps=numofsymbolerror/(N*counter); % since there are totally N symbols

pb=numofbiterror/(2*N*counter); % since 2N bits are transmitted

cm_sm33()用于高斯信道误码率的计算: function [pb1,ps1]=cm_sm33(snr_in_dB) % [pb,ps]=cm_sm32(snr_in_dB)

% CM_SM3 finds the probability of bit error and symbol error for % the given value of snr_in_dB, signal to noise ratio in dB. N=100;

E=1; % energy per symbol snr=10^(snr_in_dB/10); % signal to noise ratio sgma=sqrt(E/snr)/2; % noise variance s00=[1 0]; s01=[0 1]; s11=[-1 0]; s10=[0 -1]; % signal mapping % generation of the data source numofsymbolerror=0; numofbiterror=0; counter=0;

while(numofbiterror<100) for i=1:N,

temp=rand; % a uniform random variable between 0 and 1

if (temp<0.25), % with probability 1/4, source output is \ dsource1(i)=0; dsource2(i)=0;

elseif (temp<0.5), % with probability 1/4, source output is \ dsource1(i)=0; dsource2(i)=1;

elseif (temp<0.75), % with probability 1/4, source output is \ dsource1(i)=1; dsource2(i)=0;

else % with probability 1/4, source output is \

dsource1(i)=1; dsource2(i)=1; end; end;

% detection and the probability of error calculation

for i=1:N,

% the received signal at the detection, for the ith symbol,is:

n=sgma*randn(1,2); % 2 normal distributed r.v with 0, variance

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sgma

if ((dsource1(i)==0) & (dsource2(i)==0)), r=s00+n;

elseif ((dsource1(i)==0) & (dsource2(i)==1)), r=s01+n;

elseif ((dsource1(i)==1) & (dsource2(i)==0)), r=s10+n; else

r=s11+n; end;

% The correlation metrics are computed below

c00=dot(r,s00); c01=dot(r,s01); c10=dot(r,s10); c11=dot(r,s11); % The decision on the ith symbol is made next c_max=max([c00,c01,c10,c11]);

if (c00==c_max), decis1=0; decis2=0; elseif (c01==c_max), decis1=0; decis2=1; elseif (c10==c_max), decis1=1; decis2=0; else decis1=1; decis2=1; end;

% Increment the error counter, if the decision is not correct symbolerror=0;

if (decis1~=dsource1(i)), numofbiterror=numofbiterror+1; symbolerror=1; end;

if (decis2~=dsource2(i)), numofbiterror=numofbiterror+1; symbolerror=1; end;

if (symbolerror==1), numofsymbolerror=numofsymbolerror+1; end; end

counter=counter+1; end

ps1=numofsymbolerror/(N*counter); % since there are totally N symbols

pb1=numofbiterror/(2*N*counter); % since 2N bits are transmitted

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