第二章控制系统的数学模型例题(3)

杨平《自动控制原理》附加例题

Aω d L (Acosωt ) = L[ Aωsinωt ] = 2 2 dt S +ω 另一种解法：2

s 设x (t ) = Acosωt, x (s ) = A 2 2 s +ω x (0 ) = Acosωt t =0 = A d L x (t ) = sx (s) x (0 ) dt d s Aω 2 L (Acosωt ) = s 2 A = 2 2 dt s +ω S +ω2