l08000??14.5?52. 解：h550 ，故需要考虑纵向弯曲的影响。????..1
分
e0?ea?M380000??608mm N625?20mm
h550??18.33mm?20mm，取ea3030则ei?e0?ea?608?20?628mm????..3分
ho?550?40?510mm
?1?0.2?2.7ei628?0.2?2.7??3.52?1.0，取?1?1.0????..1分 h0510l0?14.5?15 取?2?1.0????..1分 h
??1?1e1400ih0(l02)?1?2?1?h16281400?510?14.52?1.0?1.0=1.07????..1
分
?ei?1.12?628?703.36mm
e??ei???h550?as?1.12?628??40?938.36mm，????..122分
N625000??0.319??b?0.550，故按大偏心受压计算。????..1?1fcbh01.0?9.6?400?510分
x??ho?0.319?510?162.69mm?2as?40mm
?625?10
As和As'分别
3?938.36?1.0?9.6?400?5102?0.319?(1?0.5?0.319)?2259mm2300?(510?40)????..4分
6 22(As?2281mm2)