概率论与数理统计第一章习题参考答案(6)

2019-01-19 14:58

E(XY)?1?P{X?1,Y?1}?2(P{X?1,Y?2}?P{X?2,Y?1})?4?P{X?2,Y?2}?1.8

Cov(X,Y)?E(XY)?E(X)E(Y)?0.2724 E(X)?1.9,22E(Y)?2.34

22D(X)?E(X)?(E(X))?0.6004,D(Y)?E(Y)?(E(Y))22?0.5444

?XY?Cov(X,Y)D(X)D(Y)?0.4765

22、Cov(X,Y)??XY

D(X)D(Y)??1

D(X?Y)?D(X)?D(Y)?2Cov(X,Y)?11 D(?3Y)?9D(Y)?36

Cov(X,?3Y)??3Cov(X,Y)?3

D(X?3Y?4)?D(X?3Y)?D(X)?D(?3Y)?2Cov(X,?3Y)?51

2222223、(1)E(X1(X2?4X3))?E(X1)(E(X2)?8E(X2)E(X3)?16E(X3))?17

(2)E(Xi)?12,E(Xi)?2213,2i?1,2,3

22E((X1?2X2?X3))?E(X1)?4E(X2)?E(X3)?4E(X1)E(X2)

?2E(X1)E(X3)?4E(X2)E(X3)?12

24、E(X)?

E(Y)??10dx?x?xxdy?23

?10dx?ydy?0

?xxE(XY)??10dx?xydy?0

?xx 26

Cov(X,Y)?E(XY)?E(X)E(Y)?0

Cov(X,Y)D(X)D(Y)?XY??0

则X,Y不相关。

x???dy?2x,fX(x)???x??0,0?x?1其他

?1dx?1?y,?1?y?0???y?1fY(y)???dx?1?y,0?y?1

y?0,其他??由于fX(x)fY(y)?f(x,y)在平面上不是几乎处处成立的,则X,Y不相互独立。 ?1,25、设Xi???0,P{Xi?1}?n第i号球放入第i号盒子否则P{Xi?0}?1?n

1n,1n,i?1,?,n

X??i?1Xi,E(X)??E(Xi?1i)?1

第四章习题答案

1.(1).P{Z≤1.24}=0.8925,

P{1.24<Z≤2.37==0.9911-0.8925=0.0986

P{-2.37<Z≤-1.24}=0.0986(对称)

(2) P{Z≤a}=0.9147 ? a=1.37

P{Z≥b}=0.0526 ?P{Z≤b}=0.9474 ? b=1.62

2.P{4<X≤8}=P{

4?34X?348?34<≤}

=φ(1.25)-φ(0.25)=0.2957

27

P{0≤X≤5}=P{

0?34C6≤

X?34≤

5?34}

=φ(0.5)-φ(-0.75)=0.4649

3.(1).P{| (2).P{

X?256|≤}=0.9544?

C?32C6=2? C=12

X?32>

C?32}≥0.95? ≤

X?3315575<-1.645? C<-0.29

}=0.8673

}=0.1492

4.(1).P{

2584.75?3315575≤

4390.25?3315 (2).P=P{X<2719}=P{ Y~B(25,0.1492)

X?3315575<

5752719?3315575 P{Y≤4}=P0+P1+P2+P3+P4=0.6664

P{X?6.42.3X?6.42.3??8?6.42.35?6.42.3}5.P{X>8|X>5}=

P{X?8}P{X?5}=P{

}P{X?6.4 =

P{2.3X?6.42.3?1.055}=0.1761

??0.923}6.(1).X~N(11.9,0.22) P{11.7<X<12.3}=P{ P=0.81852=0.6699

(2).1-(P{7.p{

120?160X?11.90.2?0.20.2<

X?11.90.9<

0.40.2}=0.8185

12.4?11.90.2} )2=0.0124

40?<

X?160?<

200?160?X?900.5}≥0.80?

89?900.5?>1.28 ?σ<31.2

8.(1).P{X<89}=P{<}=0.0228

28

(2).P{X≥80}≥99?P{

?

X?d0.5≥

80?d0.5}≥0.99

80?d0.5<-2.33?d>81.2

9. X~N(150,9), Y~N(100,16)

(1).W1~N(250,25),W2~N(-200,52),W3~N(125,

W1?2505242.6?2505254)

(2).P{<}=0.0694

P{|

W3?1252/5| >

52/5}=0.0456

(X?Y)?(?0.5)10.(1).P{X-Y<0}=P{<

2?0.20.52?0.2}=0.9616

X-Y~N(-0.5,2×0.22) (2).X-Y~N(-0.5,0.22+σ(X?Y)?0.5 P{<

220.2??0.50.2??222)

}≥0.90

?

0.50.2??22>1.28? σ<0.3348

11. W~N(1.63,0.0252),M~N(1.73,0.052)

(1).W-M~N(-0.1,0.0252+0.052)

(W?M)?0.10.0252 P{W-M>0}=P{

?0.05?42?0.0250.12?0.052}=0.0367

(2).P{W>1.60}=P{

5W?1.630.0251.60?1.630.025}=1-0.8849=0.1151

P=1-0.1151-0.1151×0.8849=0.8955

29

(3).

X?1.630.025/50~N(0,1)

P{X>1.60}=P{

X??16??X?1.630.025/50?1.60?1.630.025/50}≈1

12.(1).P{

P{

?X?????20??}=0.20?}=0.9?

16???20??=-0.84 ①

??由①,②解得,

?=1.28 ②

μ=17.6,σ=1.885

(2).3X+2Y-6Z~N(0,49) P{

3X?2Y?6Z7??77}=0.1587

13.(1).Z=m-X-30

(2).Z~N(m-30,7.52) (3).P{Z≥450}≥0.95?P{ ?

Z?(m?30)450?(m?30)?}≥0.95

7.57.57.5450?(m?30)≤-1.645? m≥492.4

14.(1).Z~N(m-30,32+7.52)

(2).P{Z≥450}≥0.90

?P{

Z?(m?30)450?(m?30)≥}≥0.90

22223?7.53?7.5?

15.θ=2

100450?(m?30)≤-1.28? m≥490.36

223?7.5? Y=

i?1Xi?200~N(0,1)

100?2 30


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