江苏专转本高等数学_不定积分(让你熟练掌握不定积分)(2)

2019-01-19 17:23

第三章 不定积分

=-4?(x?1)?arcsin例3.19.

2x?1?c 2?1?e?dxx2

x2x2解:原式=

1?e?ex21?e1?e1例3.20.?dx (2x?1)(3x?2)323(2x?1)?2(3x?2)dx??dx 解:原式=??dx=??3x?22x?1(2x?1)(3x?2)=?ln3x?2?ln2x?1?c 例3.21.dx=x?2?dex2x2=x?2ln(1?e)?c

x21?(x?1)2(x?1)dx 111111?x?1?x1111?x??dxdx= =??ln?c 2x?12?1?x22?(x?1)2(x?1)2x?141?x解:原式=例3.22.?1e2x?11dx 解:原式=?ex1?e?2xdx=?e?x1?e?2xdx=??de?x1?(e)?x2=?arcsine?x?c 33例3.23.secxtanxdx ?解:原式=secxtanxdsecx?(secx?secx)dsecx??22?42151secx?sec3x?C 53xarctan3x2dx 例3.24.?1?x41tan3x221132242dx?tanxd(arctanx)?arctan(x)?C 解:原式=?421?x2?82.直接交换法

a)题型

?f(ax?b)dx

(t2?b)方法:令t?ax?b,x?,

a- 83 -

?例3.25.

f(ax?b)dx?2tf(t)dt ?a?1dx x?1解:令t?原式=

x,x?t2,

1dt2tdt2dt?2=?t?1??t?1=2t?2lnt?1?c=2x?2ln(1?x)?c 1例3.26.?dx

x?2x?1?3解:令t?x?1,x?t2?1

2tt?1?1112dt?2dt?d(t?1)??t2?2t?4?(t?1)2?3?(t?1)2?3?(t?1)2?3dt

原式=

=ln(t2?2t?4)?1t?11x?1?1arctan()?C?ln(x?2x?1?3)?arctan()?C 3333dx

例3.27.

x?xx?t616t5t3)dt dt=6?(t2?t?1?解:原式6??23dt=6?x?tt?t1?t1?t=2t?3t?6t?ln(1?t)?c =2x?33x?66x?ln(1?6x)?c

例3.28.

32?13?1e?1xdx

解:原式

12t??2dt x?ln(t2?1)tt?1t?1?ex?1?ex?111?t)?c dt=ln=2?2?c=ln(xt?11?t1?e?1b) 题型

?f(ax2?b)dx

?

f(a2?x2)dx 变换x?asint

a2?x2)dx 变换x?atant

- 84 -

?f(第三章 不定积分

?f(x2?a2)dx 变换x?asect

例3.29.

?9?x2dx x解:令x?3sint,

3cost11?sin2t3costdt=3?dt?3?sintdt dt=3?原式??3sintsintsint9?x21??31?cost?39?x23 =ln?3cost?C=ln??C 221?cost239?x1?3例3.30.?x141?x2dx sec2tcos3t1?sin2tdt??4dt??dsint 解:令x?tant,原式??44tant?sectsintsint13 =?csct?csct?C 3例3.31.?x3x?42dx 解:令x?2sect, 8sec3t42tantsectdt?8sectdt 原式???2tant832=8?(1?tant)dtant?8tant?tant?C(还原略) 3 例3.32.?1?1?x?23dx 2解:令x?tant, 原式?1x2sectdt?costdt?sint?c??c ?sec3t?21?x例3.33.

?(x?2)1x?2x?22dx

- 85 -

解:令x?1?tant,

原式=

1sint?costdcostdsintdt?dt??=?sint?cost?sin2t?cos2t?1?2cos2t?1?2sin2t

=?122ln|1?2cost11?2sint。 |?ln||?C(还原略)

1?2cost221?2sint3.分部积分法

公式:udv?uv?四种基本题型 a)题型1

??vdu

?xPxedx ???m2x例3.34.(2x?1)edx

?1112x2x2x(2x?1)de?(2x?1)e?ed2x ??22212x2x =(2x?1)e?e?C

2解:原式=例3.35.e解:原式t??2x?1dx

2x?1?ettdt??tdet?tet?et?C

2x?1=2x?1e例3.36.xex22?e2x?1?C

?x2?x432dx

4?x2?1x2x42解:?xed????ed()2?2?24u??2x221x21x2uu?2uedu?2e?2?ude?2e

2444xxx1x21uu22=2ue?2e?e?C?xe?2e2?e2?C

22题型2

?P(x)cos?xdx或?P(x)sin?xdx

mm例3.37.3xsin(2x?1)dx 解:原式=

??333xdcos(2x?1)??xcos(2x?1)?cos(2x?1)dx 2?22?- 86 -

第三章 不定积分

=?33xcos(2x?1)?sin(2x?1)?C 242例3.38.xcosxdx

?1?cos2xx21dx???xdsin2x 解: 原式=?x?244x211??xsinx??sin2xdx 444x211?xsin2x?cos(2x)?C =448xdx 例3.39.?cos2x解: 原式=xdtanx?xtanx?例3.40.sin(x?1)dx 解:原式t???tanxdx?xtanx?ln|cosx?|C ?x?sin(t?1)2tdt??2?tdcos(t?1)??2tcos(t?1)??2cos(t?1)dt ??2tcos(t?1)?2sin(t?1)?C??2xcos(x?1)?2sin(x?1)?C 题型3 ?x?xeecos?xdx或?sin?xdx ?2x例3.41.ecos3xdx ?112x32x2xcos3xde?ecos3x?esin3xdx ???22212x312x32x92x2x =ecos3x??sin3xde?ecos3x?esin3x??ecos3xdx?C 2424412x32x9 =ecos3x?esin3x?C?I 24422x3ecos3x?e2xsin3x?C 解得:I?1313解:设I?ecos3xdx?2x题型4 ?P(mx)l?n(o)r(?arctan?( )dx例3.42.xln(x?1)dx

?1121x22dx 解:原式=?ln(x?1)dx=xln(x?1)??222x?1- 87 -


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