sl?x2l,dl?x2l?1sl?sl?dl?dl?211010003dl3410sl?13?24sl?11
sl?sl?dl?1s?23?1sl,dl?223?1dl2
? 第二种实现方法：根据p?(z)，由式（4－16）可求出，p(z)可表示为
??0????1???3?12?1p(z)???3?0?1???1???0?34?3?241?z?????1??1??z0?0?? 3?1??2?因此，根据算法4.3，D4小波变换的提升实现算法为
sl?x2l,dl?x2l?1dl?dl?sl?sl?211010003sl3410dl?13?24dl?11
dl?dl?sl?1sl?3?12sl,dl?13?12dl2[例4.8] db9.7小波变换的提升实现
?(z)?h?(z2?z?2)?h?(z1?z?1)?h? he420?(z)?h?(z2?z?1)?h?(z?1) h031?(z)存在以下因子分解： 可以求出，p?1?(z)??p?0?(1?z)??1?11?????(1?z)0??1??1??0?(1?z)??1?11?????(1?z)0??1?????00?? 1/???/h?，??h?/r，??r/s，??s/t，??t?r?2r 其中，??h00110004331??2h?h?/h?，r?h??h??h?h?/h? r0?h0413124413??h??h?r/r，t?r?2r s0?h00113301所以，由式（4－6）可得
1?p(z)?????(1?z)0??1??1??0??(1?z)??1??11?????(1?z)0??1??1??0?1??(1?z)??1/???1??00?? ??根据算法4.3 db9.7正向小波变换的提升算法为：
s00l?x2l,dl?x2l?1.d10??(s00l?dll?sl?1)
s1011l?sl??(dl?dl?1)d2l?d111l??(sl?sl?1)s2122l?sl??(dl?dl?1)sl???s2d2l,l?dl/?