绵阳市高2013级第一次诊断性考试
理科综合能力测试 生物部分参考答案及评分标准
第Ⅰ卷（选择题，共42分）
在每题给出的四个选项中，只有一个选项是最符合题目要求的。共7题，每题6分。 1.B
2.D
3.D
4.C
5.C
6.A
7.B
第Ⅱ卷（选择题，共48分）
8.（10分）
（1）细胞质基质和线粒体（1分） 由线粒体移向叶绿体（1分） （2）4（1分） 12（1分） （3）36（1分） 弱（1分）
（4）上移（2分） 植物对绿光吸收很少，光合作用减弱，呼吸作用不变，吸收的CO2将减少（2
分）
9.（14分）
（1）限制酶（2分，答限制性核酸内切酶也得分） DNA连接酶（2分） （2）抗生素Kan（2分） （3）深褐色（2分） （4）多了2个（2分）
（5）所有生物都共用一套密码子表（2分） （6）受精卵（2分，答卵细胞也得分） 10.（9分）
（1）RrrrYYyy（1分） 基因突变（1分） （2）雌（1分） 1（1分） （3）卵巢（1分） （4）4（1分） 次级卵母细胞（1分）
（5）
（2分，染色体1分，基因组成1分。）
11.（15分） Ⅰ
（1）XAXa（1分） XaY（1分） （2）雌雄个体全部为短毛（1分） Ⅱ
（1）1∶1（2分） 1∶3（2分） （2）1/6（2分）
（3）①X（2分） ②B（2分） ③1/2（2分）
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绵阳市高2013级第一次诊断性考试
理科综合能力测试 物理部分参考答案及评分标准
第Ⅰ卷（选择题，共42分）
在每题给出的四个选项中，只有一个选项是最符合题目要求的。共7题，每题6分。 1.C
2.D
3.A
4.B
5.B
6.AC
7.BD
第Ⅱ卷（选择题，共 分）
8.（16分）
（1）①AC（3分）；②A（3分）。 （2）①CD（2分）；②1.56（3分）；能（2分）;
③9.70～9.90都给分（3分）。
9. （15分）
（1）设“嫦娥一号”的质量是m1，则
2Mm4?1 G?m1(R?H)2 ??????(4分) 2T?R?H?4?2(R?H)3 ??????(2分)
M?GT2(2)设月球表面的重力加速度为g，则 GMm?mg ??????(3分) 2Rr?2 ············································································································· (4分) F?mg?m4?2(R?H)3m?2解得F?·············································································· (2分) ?m ·22RTr 10．（17分）
（1）设小滑块上滑的加速度大小是a1，则 ma1= mgsinθ＋μmgcosθ ···························································································· (2分) v0=a1t ·························································································································· (2分) 解得a1=7.2 m/s2，t =2.5 s ·························································································· (2分)
（2）小滑块从斜面底端上滑到最高处的过程中，设沿斜面上滑的距离是x，根据动能定理有
0－
12=－mgh－μmgxcosθ ················································································· (2分) m?02h= xsinθ ······················································································································ (2分) 解得h=13.5 m ············································································································ (2分) 另解：2a1x=?0 ········································································································ (2分)
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2h= xsinθ ······················································································································ (2分) 解得h=13.5m ··········································································································· (2分) （3）根据功能关系有△E=2μmgxcosθ ···································································· (3分) 解得△E = 10.8 J ········································································································· (2分) 11.（20分）
解：（1）设小滑块能够运动到C点，在C点的速度至少为vc，则
?c2 ·················································································································· (2分) mg?mR112············································································· (2分) m?c2?m?0??2mgR??mgL ·22解得v0=215m/s ····································································································· (1分)
(2)设传送带运动的速度为v1，小滑块在传送带上滑动时加速度是a，滑动时间是t1，滑动过程中通过的距离是x，则 v1=rω ······················································································································ (1分) ma=μmg ···················································································································· (1分) v1=at1 ························································································································ (1分)
x?12 ···················································································································· (1分) at1·
2解得v1=2m/s，a=4m/s2，t1=0.5s，x=0.5m
由于x＜L，所以小滑块还将在传送带上与传送带相对静止地向B点运动，设运动时间为t2，则 L－x= v1t2 ················································································································· (2分) 解得t2=2.25s
则t= t1＋t2=2.75s ······································································································ (2分)
（3）轮子转动的角速度越大，即传送带运动的速度越大，小滑块在传送带上加速的时间越长，达到B点的速度越大，到C点时对圆轨道的压力就越大。
小滑块在传送带上一直加速，达到B点的速度最大，设为vBm，对应到达C点时的速度为vcm，圆轨道对小滑块的作用力为F，则
2················································································································ (2分) ?Bm?2aL ·
1122······················································································· (2分) m?cm?m?Bm??2mgR ·
22RFm=F ······················································································································· (1分)
2?cm ········································································································· (1分) mg?F?m解得Fm=5N ·············································································································· (1分)
绵阳市高中2013级第一次诊断性考试 理科综合 化学部分参考答案和评分标准
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第Ⅰ卷（选择题 共42分）
选择题（共7小题，每小题6分。在每小题给出的四个选项中，只有一项是符合题目要求的） 1. D 2. C 3. D 4. A 5. B 6. C 7. B
第Ⅱ卷（共58分）
8.（共14分，每空2分）
（1）1s22s22p63s23p63d104s1（或[Ar]3d104s1）
H‥－
（2）d （3）sp3杂化 正四面体 [ H∶N∶]
‥
4×993
（4）CuCl 23 cm6.02×10ρ9.（共14分）
c(CH3OH)
（1）（1分） （2）0.25（2分） 0≤x≤7（3分）
c(CO)·c2(H2)
（3）-90.1 kJ/mol（2分）
（4）① 0.3 mol·L-1·min-1（2分） ② 50%（2分） ③ a（2分） 10.（共14分）
+2+
（1）CaCO3＋2H==Ca＋CO2↑＋H2O（2分）
250 mL容量瓶、玻璃棒、胶头滴管（2分） b a d（2分） g h c（2分） （2）56.3%（3分） （3）CDE（3分）
11.（共16分）
（1）能水解生成吸附能力很强的胶体（1分） （2）1×10-15（2分，答为4×10-15给1分） 调节溶液的pH 促进Al3+水解转化为沉淀完全除去
（2分）
－
（3）Fe2+＋NO2＋2H+==Fe3+＋NO↑＋H2O（2分） 112（3分） （4）
操 作 取少量溶液于试管中，滴加0.05 mol/L酸性高锰酸钾溶液 现 象 溶液不褪色 取少量溶液于试管中，滴加0.1 mol/L BaCl2溶液，再滴加20% HNO3溶液 产生白色沉淀 （操作每空2分，现象每空1分，共6分）
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