X2(k)= X(z)1 e 1 e=
z=
2 e jN k
= WN
k
1 z 5 2 = 1 z 1 z= e j N k
=
2 5k j 5 j 2 k 5
2 N=5, = k 5
5
k=0
0 k=1,2,3,4
3-1 离散傅里叶级数(16)
2020-11-27 11:11
3-1 离散傅里叶级数(16).doc
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X2(k)= X(z)1 e 1 e=
z=
2 e jN k
= WN
k
1 z 5 2 = 1 z 1 z= e j N k
=
2 5k j 5 j 2 k 5
2 N=5, = k 5
5
k=0
0 k=1,2,3,4
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