高频电子线路课后习题 - - 张肃文

2019-01-19 14:44

3?1解:f0?1MHz632Δf0.7?1?10?990?10Q?f02Δf0.7QR?1?1063?10(kHz)10?10?100取R?10Ω则L?C?

?012??100?102?3.14?106?159(?H)?159(pF)1(2?3.14?10)?159?101L1C11L1C11L1C162?6?0L

3?2解:(1)当?01?或ω02?1L2C21L2C21L2C2时,产生并联谐振。时,产生串联谐振。(2)当?01?(3)当?01?或ω02?或ω02?1jω0C1jω0C时,产生并联谐振。2(R?jω0L)(R?3?3证明:Z?R?jω0L?R?3?4解:1?由?15?C??16052)?R?LC?jω0LR(1? 1ωLC1)20)?R?2R2LC?R2R?jω0L(1?2ω0LC2

??450?C?535得C?40pF2由?12?C??1605故采用后一个2?L?3?122??100?C?535得C?-1pF?不合理舍去??180?μH。?1?0?C?C???2?3.14?535?10???45032?40??10?12?

L C C’

3?5解:Q0?1?0C0R120?12?3.14?1.5?10?100?10162-126-12?5?212L0??C0VomR???2?3.14?1.5?10?100-3?112?μH??10Iom?1?105?0.2?mA?-3VLom?VCom?Q0VSm?212?1?10?212?mV?

3?6解:L?1?CVCVS??20?1?2?3.14?10??100?62?100?10?12?253?μH?Q0?100.1120C?CXC?CXRX?1?L??2?3.14?10??626?253?10?6?100?pF??CX?200pF2?3.14?10?253?10100?126?6?0LQ?0LQ012?3.14?10?253?102.50.1?47.7?j?6??47.7?Ω?ZX?RX?j12?3.14?10?200?10?12?0CX6?47.7?j796?Ω?3?7解:L?1ω0Cf02?1?2?3.14?5?10??50?106?20.2?μH?Q0?2Δf0.72Δff0?5?1063150?101003??100366ξ?Q0?2??5.5?5??105?10?20321kΩ电阻。

??2?2?f0.7,则Q?因2Δf0.7?0.5Q0,故R??0.5R,所以应并上03?8证明:4πΔfC?0.72πf0Cf02Δf0.7?ω0CQ?g?3?9解:C?Ci?12π?C2??C0?C1C2?C0?C12?3.14?100??5?

?20?20?2020?20?201?6?18.3?pF??f0?LCLC120.8?10?18.3?10?6?12?12?41.6?MHzRP?Q00.8?10?20?20??102?20.9?kΩ?2?C2?C0?C1??20?20?20??R??RiRP?R?1020.9???5?5.88?kΩ?0??C120????QL?R?ω0L?f0QL5.88?10663?62?3.14?41.6?10?0.8?10?41.6?1028.2?1.48?MHz?28.22Δf0.7??

3?12解:1?Zf1?02?Zf1?03?Zf1?R

3?13解:1?L1?L2?C1?C2?M?ηR1ρ1?011201?10362?3.14?10??159?μH1??159?pF?L1??2?3.14?10?662?159?10?6?1?202?3.14?10??01?3.18?μH6??622?Zf1???01M?2R2L1?2?3.14?10??3.18?10?6?20159?10?20?Ω?ZP?3?Q1??R1?Rf1?C1??20?20??159?106?12?25?kΩ??01L1R1?Rf121???02f0Q2?3.14?10?159?1020?202f0ρ1R16?6?25?28.2?kHz4?2Δf0.7???5?C2???2?110?2010323???2L2?2?3.14?950?????10??159?10?6?177?pF?1Z22?R2?j??L??021?C?022?1??6?6?20?j?2?3.14?10?159?10??20?j1006?12?2?3.14?10?177?10??Zf1???01M?2Z22LRPC???2?3.14?10159?103?66?3.18?10?62?20?j100?12?0.768?j3.84?Ω?

3?15解:?R?50?10?159?10?20????R1?Rf1?0?M?0Q?2f02?f0.7?2106314?10?100

?623?16解:1?Rf1???01M?2R2??107?105??20????62Rab?2???3?Q??RR1??01L?21?Rf1?7??107?100?105?20??40?k???01M?01LR1f0??10?1057?6?2?6?10?100?105?200?2?2?2?1?22?f0.7??2??1?21Q1200?0.013

3?17解:II0?1?2?f?1??Q?f0?1????2?13?10?10?1???Q300?103?????2?11.25?Q??22.5R?II0?Q?0C?1122.5?2?3.14?300?10?2000?1023?12?11.8?13?10?101???Q300?103??2?f1???Qf0?1L2C1?L2?C????????2?12?Q?30Q?Q??30?22.5?7.5?2ω???3?18解:??ω??L1??

?L1?375μH???L2?125μ串联联谐并联联谐

β0?β0f1???f?T????24?5解:当f?1MHz时,???50?50?1061???250?106?????2?49当f?20MHz时,??β0?β0f1???f?T????2?50?50?20?1061???250?106?????2?12.1当f?50MHz时,??β0?β0f1???f?T????2?50?50?50?101???250?106?6????2?5

4?7解:gb?e?gm?Cb?e?IE26?β0?1??126??50?1??3?0.754?mS?β0rb?e?50?0.754?10?37.7?mS??gm2πfT?37.7?10?362?3.14?250?10?24?pF?3a?1?rbb?gb?e?1?70?0.754?107?1?12b?ωCb?erbb??2?3.14?10?24?10yie??70?0.1?3?gb?e?j?Cb?e??a?jb?a?b22??0.754?10?j2?3.14?10?24?101?0.1227?12???1?j0.1??0.895?j1.41?mSyre??yfe????j2?3.14?10?3?101?0.12227?12?gb?c?j?Cb?c??a?jb?a?b22?3??1?j0.1???0.0187?j0.187?mS?gm?a?jb?a?b22?37.7?102??1?j0.1?1?0.1?37.327?j3.733?mS?yoe?gce?j?Cb?c?rbb?gm7?gb?c?12?j?Cb?c??a?jb?a?b22a?jb???j?Cb?c?1?rbb?gm22?a?b???j2?3.14?10?3?10?Av??4?8解:令??A??vo??Av??令??A??vo?mm1?j0.1???3?0.049?j0.68?mS?1?70?37.7?10?22?1?0.1??????m??????2?4??Q2Δf20.7f0?4??12得2Δf0.7?4?1?f0m?42?1????Q??2m??????4??Q2Δf40.1f0?4?????m?110得2Δf0.1?4?4?10???f?1??0?Q?故Kr0.1?2Δf0.12Δf0.7?4?4?10??2m??1???2?410m1?1?1?m?42?1?????2m?1


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