4?9解：p1?gp?N23N131?520?2?0.25p2?1N45N13?520?0.25?37.2?μS?6ω0Q0L2π?10.7?10?100?4?102?66?6??142g??gp?p1goe?p2gie?37.2?10Avo?p1p2yfegΣ2??3142?200?10?2860?10?6?228.5?μS??20.25?0.25?45?10228.5?10?6?12.3Apo?Avo?12.3?151.3QL?1gΣω0Lf0QL?1228.5?1010.7?1016.3?26?6?2π?10.7?10?4?10Z6?6?16.32Δf0.7???0.657?MH?2??QL??K??1??Q0???ξ?tang??LS?16.3????1??100??o?1.43o?fe??re22?tan??54?88.52?6??2.952?6gp?p2giep2137.2?10?0.25?200?100.252?63008.8?μS??6?gs??1?ξ?gie??goe?g?Lyfeyre2??2?2860?10?200?10?6?3008.8?10?345?10?30.31?10??1?2.95???12
?1?gp?4?10解：1Q0ω0L1?1100?2?3.14?10.7?10?4?10226?6?0.037?mS?2g??gp?R5?p1goe?p2gie??0.037?0.1?0.3?0.082?0.3?0.15??0.158?mS2?Avo?p1p2yfeg??0.3?0.3?38?4.2220.158?21.7862?2?2Δf0.7?3??Avo?4?ω0Lg?f0?2?3.14??10.7?10??Avo??21.78414??4?10?6?0.158?10?3?454.4?kHz??225025.381?4??2Δf0.7?4?5?2Δf0?.7??24?1?2Δf0.7??1044.6?kHz24?1?454.4?197.65?kHz?2Δf0.71??24?12Δf0?.7?2Δf0.7?1044.6?454.4?590.2?kHz??Avo??4?Avo?Avo?4Avo2Δf0.72Δf0?.74?21.78?454.41044.64?9.47???9.47??Avo2?8042.66??4?225025.38-8042.66?216982.72??Avo2
4?11解：C??C?p1Coe?500?0.3?18?501.62?pFL?1??12?2πf0?2C??1?2?3.14?1.5?10?262?22.5?μH?
?501.62?10Kr0.1?1.9不能满足?Avo?S?4?14解：yfe2.5?0Cre?26.4?36.42.5?0.32?7.74
4?17解：L1?1ωC120?1?2π?465?10?11873?7332?1000?10?60?11873?12?118?μH?L36?L2?L34?L56?118?13.5?120C12?C1?Co?1000?4?1004?pF2???12C36?13.5??C2?pCi?1000????40?1004?pF?74.5?22g12?go?22ω0C1Q0?20?10?6?22π?465?10?1000?101003?49?μS3??12g36?pgi?ω0C2Q02π?465?10?1000?10?13.5??3???0.62?10??100?74.5?。若为临界耦合，即?40?10?3?49?μS??初、次级回路参数相等p1p2yfegω0C12g122?f0QL1??13.5??1，则Avo?QL?74.5?62?49?103?74?122π?465?10?1004?1049?10?2?465?1060?63?602Δf0.7??10.9?kHZ?
Kr0.1?3.164?20解:2vn?in?224kTRΔfn?4kTGΔfn?2224?1.38?104?1.38?10?23?23?290?1000?10-37?12.65?μV?
?290?10?107?12.65?nA?4?21解：?vn?vn1?vn2?vn3?4kT1R1Δfn?4kT2R2Δfn?4kT3R3Δfn?4k?T1R1?T2R2?T3R3?Δfn?4kT?R1?R2?R3?Δfn?T?2T1R1?T2R2?T3R3R1?R2?R3222又?in?in1?in2?in3?4kT1G1Δfn?4kT2G2Δfn?4kT3G3Δfn?4k?T1G1?T2G2?T3G3?Δfn?4kT?G1?G2?G3?Δfn?T?T1G1?T2G2?T3G3G1?G2?G3?R1R2T3?R2R3T1?R3R1T2R1R2?R2R3?R3R1
4?18证明：1?Ib1?yieV???be1??yreV?ce1???1????2?????yieVce1?yre?V?????cb2?Vce1??yreV???cb2?Vce1??yoeV??ce1??cb2?be1Ic1?yfeV???yoeV?ce1Ib2?yieV??be2?yreV?ce2??yie?yre?V?ce1???3????4?Ic2?yfeVbe2?yoeVce2????yfeVce1?yoe?V???yie?yre?yoe?V?be1?cb2??yfe?yoe?V?ce1?2???3?得????be1Ic2?yfeV?cb2?yreVcb2Vce1?Ic2?yreV?yfeVyie?yre?yoe?????5???cb2??5?代入?4?Ic2??yoeVcb2??yfe?yoe?Ic2?yreV?yfeV2be1yie?yre?yoe?Ic2??yf?yo?yfe?yfe?yoe??2?yie?yre?yfe?2yoeyfe?yfe?yoeVbe1?yieyoe?yreyfe?yoeyie?yre?yfe?2yoeVcb2???6?yie?yre?yfe?2yoe?yfeyieyoe?yreyfe?yoeyie?yre?yfe?2yoe??yre由?1?乘?yfe?yoe?与?4?乘yre后相加得Ib1?yfe?yoe??Ic2yre?yie?yfe?yoe?V由?6?代入消去?2????be1??yreyoeVcb2Ic2得?Ib1?yie?yieyre?yieyfe?2yieyoe?yreyfeyie?yre?yfe?2yoeyie?yieyre?yieyfe?2yieyoe?yreyfeyie?yre?yfe?2yoeyre?yoe?yre略?23Vbe1?yre?yoe?yre??yie?yre?yfe?2yoeVcb22yi?yr??yie?yie?yre?yfe?2yoe??yre?yoe?yreyfe?同理可证2?24?22解：vbn?4kTrb?fn?4?1.38?10ien?2qIE?fn?2?1.6?102?19??273?19??70?200?10?33?0.226?10?12?V?2?10?200?10?0.953?0.64?10?16?A?2???0?f??1???f????2?0.95?10?1061???500?106?????2icn?2qIC?1??0??fn?2?1.6?102?19?10?3??1?0.95??200?103?0.32?10?17?A?
24?23证明：?fn???0AA2?f?df?f0?2???1?f?f01??2Q?f0?????20df??f02Q4?24解：Fn高?3dB?1.995倍?Fn混?1?TiT?1?60290?Fn中?6dB?3.981倍??1.207Fn中?1?1.995?1.207?1Ap高?
Fn?Fn高?Ap高?1.888Fn混?1Ap高3.981?10.2?Ap高KpcAp高?1020lg1.888?2.76?dB??24?25解：Fn?4?26解：Fn?PsiPniPsoPnoPsiPniPsoPno?PnoPniAp1Ap??PsPo1Ap??1PoPsPsPo?VsVs224Rs4?Rs?R?? Rs?RR?1?RsR
?Is4GsIs4?Gs?G?GL?rCL?2?1?G?GL?rCLGs4?27解：A为输入级，B为中间级，C为输出级。APA?6dB?3.981倍?Fn?FnA?FnB?1ApA?ApB?12dB?15.849倍?FnC?1ApA?ApB?1.7?2?13.981?4?13.981?15.849?2 1.995?110?0.14?28解：不能满足要求。设Fn?PsiPniPsoPno2A前置放大器，?FnA?FnB?1ApA2B为输入级，FnC?1?FnA?C为下一级。10?110??FnA?8.1?101054?ApA?ApB
5?8解：i?kv?k?V0?Vmcos?0t?1212?2?2?k?V0?2V0Vmcos?0t?Vm?Vmcos2?0t?22??当Vm??V0时，i?k?V0?2V0Vmcos?0t?，该非线性元件就能近2似当成线性元件来处理Vm很小时，根据泰线弯曲部分，故，即当V0较大时，静态工作点选勒级数原则，可认为信可只取其级数的前两项在抛物线上段接近线性部分，然后当号电压在特性的线性范得到近似线性特性。围内变化，不会进入曲o5?12解：为了使cos60oiC中的二次谐波振幅达到?VBZ?VBBVm?12最大值，?C应为60。12Vm?VBZ?VBB?