故答案为:IO3-+5I-+6H+═3H2O+3I2; ②设需要加入NaIO3为x, IO3-+3HSO3-═3SO42-+I-+3H+, 1 3 1 53 5 53 IO3-+5I-+6H+═3H2O+3I2 1 5 3 (x-53)5(x-553) 3(x-3) 5则:n(I?)3?5(x?53)n(I??a;2)3(x?5 3)解得:x=5a?103a?5. 故答案为:5a?103a?5.
16
故答案为:IO3-+5I-+6H+═3H2O+3I2; ②设需要加入NaIO3为x, IO3-+3HSO3-═3SO42-+I-+3H+, 1 3 1 53 5 53 IO3-+5I-+6H+═3H2O+3I2 1 5 3 (x-53)5(x-553) 3(x-3) 5则:n(I?)3?5(x?53)n(I??a;2)3(x?5 3)解得:x=5a?103a?5. 故答案为:5a?103a?5.
16