(3)假设存在实数a,使f?x??ax?ln??x?有最小值3,x???e,0?
f'?x??a?1e1x
①当a??时,由于x???e,0?,则f'?x??a?1?0 x?函数f?x??ax?ln??x?是??e,0?上的增函数?f?x?min?f??e???ae?1?3
41??(舍去) ee111②当a??时,则当?e?x?时,f'?x??a??0此时f?x??ax?ln??x?是减函数
axe解得a??
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(3)假设存在实数a,使f?x??ax?ln??x?有最小值3,x???e,0?
f'?x??a?1e1x
①当a??时,由于x???e,0?,则f'?x??a?1?0 x?函数f?x??ax?ln??x?是??e,0?上的增函数?f?x?min?f??e???ae?1?3
41??(舍去) ee111②当a??时,则当?e?x?时,f'?x??a??0此时f?x??ax?ln??x?是减函数
axe解得a??
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