case 2: count[2]++; break; case 3: count[3]++; break; case 4: count[4]++; break; case 5: count[5]++; break; case 6: count[6]++; break; case 7: count[7]++; break; case 8: count[8]++; break; case 9: count[9]++; break; case 10: count[10]++; break;
default: printf(\}
}
printf(\for (grade=1; grade<=GRADE_SIZE-1; grade++)
{ printf(\ for (j=0; j { printf(\ } printf(\ } } 解法二: #include int i, j, grade; int score[STUDENTS], count[GRADE_SIZE] = {0}; printf(\ students:\\n\ 36 for (i=0; i scanf(\ } for ( i=0; i { count [ score[ i ] ] ++; } printf(\for (grade=1; grade<=GRADE_SIZE-1; grade++) { printf(\ for (j=0; j { printf(\} printf(\ } } 2. 大奖赛现场统分 #include int i,j,k; float pf[N][M],sf[N],max,min,sum,temp; system(\ for(i=0;i printf(\ performance:\\n\ 37 for( j=0;j scanf(\ } for(i=0;i sum=0.0; max=pf[i][0]; min=pf[i][0]; for(j=0;j if (max else if(min>pf[i][j]) min=pf[i][j]; sum=sum+pf[i][j]; } sf[i]=(sum-max-min)/(M-2); printf(\ is:%.2f\ } for(i=0;i k=i; for(j=i+1;j if(sf[k] if(k!=i) { temp=sf[i]; sf[i]=sf[k]; sf[k]=temp; } } printf(\ for(i=0;i printf(\} 38