第2章 工艺计算书
同理得：Tpj?39.383℃
??pj?45.24cp
?pj?885?(1.825-0.001315?885)??39.383?20??872.18kg/m3
165.34?0.1896m3/s
872.1845.24?10?3?pj??51.87?10?6m2/s
872.181.750.1896?(51.87?10?6)0.25?i?0.0246??0.009889
0.39064.75Qmax?a?8.528?10?6
165.34?9.8?0.009889b??5.411℃
2.2432???0.4204?TR??T0?b???TZ?T0?b?eaLR?（1?5.411）?（33?1?5.411）e同理得：Tpj?38.304℃
8.528?10?6?55?103?48.912km
??pj?46.85cp
?pj?885?(1.825-0.001315?885)??38.304?20??872.90kg/m3
165.34?0.1894m3/s
872.9046.85?10?3?pj??53.67?10?6m2/s
872.901.750.1894?(53.67?10?6)0.25?i?0.0246??0.009955 4.750.3906Qmax?（2）最小输量下： 取TZ?33℃ LR?L8?55km
令b=0 则TR??T0?b???TZ?T0?b?eaLR ?（1?0）?（33?1?0）e1.218?10同理得：Tpj?43.187℃
?5?55?103?63.5℃
??pj?39.99cp
?pj?885?(1.825-0.001315?885)?43.187?869.67kg/m3
- 29 -
第2章 工艺计算书
115.74?0.13308m3/s
869.6739.99?10?3?pj??45.98?10?6m2/s
869.671.750.13308?(45.98?10?6)0.25?i?0.0246??0.005165
0.39064.75Qmin?a?1.218?10?5
115.74?9.8?0.005165b??1.978℃
2.2432???0.4204?TR??T0?b???TZ?T0?b?eaLR?（1?1.978）?（33?1?1.978）e同理得：Tpj?42.547℃
1.218?10?5?55?103?61.64km
??pj?40.82?10?3Pa·s
?pj?885?(1.825-0.001315?885)??42.547?20??870.09kg/m3
115.74?0.13302m3/s
870.0940.82?10?3?pj??46.91?10?6m2/s
870.091.750.13302?(46.91?10?6)0.25?i?0.0246??0.005187
0.39064.75Qmin?2.4.2 热力、水力校核 （1）热力校核
已知：Qmax?0.19019m3/h?684.68m3/h Gmax?165.34 a?8.528?10?6
L=55km
设 ：TZ?33℃ 初取b=5.411℃
TR??T0?b???TZ?T0?b?eaLR
?（1?5.411）?（33?1?5.411）e8.528?10同理得：Tpj?38.304℃
i=0.009955
?6?55?103?48.91℃
165.34?9.8?0.009955?5.447℃
2.2432???0.4204?TR??T0?b???TZ?T0?b?eaLR
b?- 30 -
第2章 工艺计算书
?（1?5.447）?（33?1?5.447）e8.528?10?6?55?103?48.89km
? 满足热力要求，b值与假设相近，计算符合要求。
同理在最小输量下计算得：满足热力要求，b值与假设相近，计算符合要 （2）水力校核 管道承压： H承压?P?g?6.86MPa869.35?9.8?805.20m
①最大输量下八个热泵站全开，只能对泵站进行拆级使用。 设首站进站压力Hs1?50m 首~2#
?Hd?H泵?Hs1?567.72?50?617.72m?55?103?(33?18)?30?592.525m [H]?iLR??Z?hm?0.009955?H剩?25.195m八级泵
2#~3#
?Hd?H泵?Hs1?567.72?25.195?592.915m[H]?iLR??Z?hm?0.009955?55?103?10?30?567.525m?H剩?25.39m八级泵
3#~4#
?Hd?H泵?Hs1?638.69?25.39?664.08m[H]?iLR??Z?hm?0.009955?55?103?10?30?587.525m?H剩?76.555m九级泵
4#~5#
?Hd?H泵?Hs1?567.72?76.555?644.275m[H]?iLR??Z?hm?0.009955?55?103?9?30?568.525m?H剩?75.75m八级泵
5#~6#
- 31 -
第2章 工艺计算书
?Hd?H泵?Hs1?567.72?75.75?643.47m[H]?iLR??Z?hm?0.009955?55?103?8?30?585.525m?H剩?57.945八级泵
6#~7#
?Hd?H泵?Hs1?567.72?57.945?625.665m[H]?iLR??Z?hm?0.009955?55?103?14?30?591.52m?H剩?34.14m八级泵
7#~8#
?Hd?H泵?Hs1?567.72?34.14?601.86m[H]?iLR??Z?hm?0.009955?55?103?6?30?571.525m?H剩?30.335m八级泵
8#~末站
?Hd?H泵?Hs1?567.72?30.335?598.055m[H]?iLR??Z?hm?0.009955?55?103?22?30?55.525m?H剩?42.53八级泵
出站压力经校核满足要求。
②最小输量下开四个热泵站四个热站 首~3#
?Hd?H泵?Hs1?631.35?50?681.35m[H]?iLR??Z?hm?0.005187?110?103?5?30?605.57m ?H剩?Hd?[H]?75.78m九级泵
3#~5#
?Hd?H泵?Hs1?561.2?75.78?636.98m[H]?iLR??Z?hm?0.005187?110?103?1?30?601.57m ?H剩?35.41m 八级泵
5#~7#
- 32 -
第2章 工艺计算书
?Hd?H泵?Hs1?631?35.41?666.41m[H]?iLR??Z?hm?0.005187?110?103?22?30?622.57m ?H剩?43.84m九级泵
7#~末站
?Hd?H泵?Hs1?561.2?43.84?605.4m[H]?iLR??Z?hm?0.005187?110?103?28?30?572.57m ?H剩?32.47m 八级泵
出站压力经校核满足要求。
2.5 反输计算
2.5.1 反输量确定
在建设初期投产运行之前要进行反输计算，以最小输量计算。 其中： 取TR?61.63℃；Tz=33℃。 由Gmin?
K?DlR 得：
TRmax?T0clnTzmin?T02.2432?3.14?0.4064?55?103Gm??118.71kg/s>70%Gmax
62.87?12.1?ln33?1=Gmin=115.74kg/s
所以反输量G=Gmin=115.74kg/s 2.5.2 翻越点判断
Tpj?12?61.63??33?42.543 ℃ 33?42.543?885?0.661225?22.543?870.094kg/m3
Gmin2.2432?3.14?0.4064?55?103??117.31kg/s〉70% Gmax
61.63?12.1?ln33?1所以：Gmin=115.74kg/s
Qmin=G/?=115.74/870.094=0.13302m3/s=478.87 m3/h
- 33 -