a?an?1n4?1?2?1??221?4n?
?n?2n42?43?2n?1?.
2当n为奇数时,则n+1为偶数,Tn?1??n?1??2?n?1?4?43?2n?1?1?
?n?4n?342?43?2n?1?1?,
而Tn?1?Tn?bn?1?Tn?2n?4n?3422n?1,
43∴ Tn??13?2n?1?.
?n?2n2n?14??2??n为偶数???433∴ Tn??.
2?n?4n?3?1?2n?1?4n为奇数???433?n2(III) P?4?24n,设dn?Tn?P?n?N*?,
当n为奇数时,dn?若dn?2?dn?2n?113?2n?1?472n?712,
?47?0,则n≥5,
∴ 从第5项开始?an?的奇数项递增而d1,d3,?,d11均小于2011且d13?2011, ∴ 此时dn?2011; 当n为偶数时,dn?若dn?2?dn?2n?223?2n?1?472n?43,
?47?0,则n≥4,
∴ 从第4项开始?an?的偶数项递增而d2,d4,?,d10均小于2011且d12?2011, ∴ 此时dn?2011, 综上可知dn?2011?n?N*?即Tn?P?2011?n?N*?,
因此李四同学的观点是正确的.
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