LsLs450′50504p2=-=-=0.52(m) 3324R2384R24创2002384200Ls50=28.6479?7.16 R200a29.37T2=(R+p)?tgq=(200+0.52)?tg24.99=77.56(m)
22ppL2=(a-2b)R+2LS=(29.37-2创7.16)200+100=152.56(m)180180b2=28.64792
E2=(R+p)seca29.37-R=(200+0.52)?sec200=7.30(m) 22J2=2T-L=2?77.56152.56=2.56(m) 主点桩号计算： ZH=K4+797.45
HY=ZH+Ls= K4+797.45+50=K4+847.45
QZ=HY+(L-2Ls)/2=K4+847.45+(152.56-2×50)／2=K4+873.73 YH=HY+(L-2Ls)= K4+847.45+(152.56-2×50)=K4+900.01 HZ=YH+Ls= K4+900.01+50= K4+950.01 ③JD3—CDE段
11
T3（D）JD3αE33L33R3αLsJD2（C）Lso3JD
图2.4
'\已知 a3=13?5904.8 , 取圆曲线半径 R3=430m ，如上图: '\Ls=50m, a1=13?5904.8，换算为度为14.0°
LsLs350503q3=-=-=25.0(m)
2240R22240创430430LsLs450′50504p3=-=-=0.24(m) 3324R2384R24创4302384430Ls50=28.6479?3.33 R430a14T3=(R+p)?tgq=(430+0.24)?tg25=77.77(m)
22ppL3=(a-2b)R+2LS=(14-2创3.33)430+2?50154.95(m)
180180a14E3=(R+p)sec-R=(430+0.24)?sec430=3.47(m)
22b3=28.64792 12
4（E）ZHαHZ
J3=2T-L=2?77.77154.95=0.58(m) 主点桩号计算： ZH=K5+038.61
HY=ZH+Ls= K5+038.61+50=K5+088.61 QZ=HY+(L-2Ls)/2=K5+116.09
YH=HY+(L-2Ls)= K5+088.61+(154.95-2×50)=K5+143.56 HZ=YH+Ls= K5+143.56+50= K5+193.56 ④JD4—DEF段
T4L4HZLs4αLsR4αoJD3）D（4图2.5
'\已知 a4=41?5114.8 , 取圆曲线半径 R4=160m ，如上图: '\Ls=50m, a1=41?5014.8，换算为度为41.84°
LsLs350503q4=-=-=24.98(m) 22240R2240创160160LsLs450′50504p4=-=-=0.65(m) 3324R2384R24创16023841602 13
ZH）E4（JDα4E4）F5（DJ
b4=28.6479Ls50=28.6479?8.95 R160a41.84T4=(R+p)?tgq=(160+0.65)?tg24.98=86.39(m)
22ppL4=(a-2b)R+2LS=(41.84-2创8.95)160+2?50166.83(m)180180a41.84-R=(160+0.65)?sec160=11.99(m) 22
E4=(R+p)secJ4=2T-L=2?86.39166.83=5.94(m) 主点桩号计算： ZH=K5+310.88
HY=ZH+Ls= K5+310.88+50=K5+360.88
QZ=HY+(L-2Ls)/2=K5+360.88+(166.83-2×50)/2=K5+394.29 YH=HY+(L-2Ls)= K5+360.88+(166.83-2×50)=K5+427.71 HZ=YH+Ls= K5+427.71+50= K5+477.71 ⑤JD5—EFG段
14
Go5α5R5L54（DJE）ZHLsE5α55（DJF）
T5图2.6
'\已知 a5=50?4313.9 , 取圆曲线半径 R5=130m ，如上图: '\Ls=50m, a5=50?4313.9，换算为度为50.72°
LsLs350503q5=-=-=24.97(m)
2240R22240创130130LsLs450′50504p5=-=-=0.80(m) 3324R2384R24创1302384130b5=28.6479Ls50=28.6479?11.02 R130a50.72T5=(R+p)?tgq=(130+0.80)?tg24.97=86.97(m)
22ppL5=(a-2b)R+2LS=(50.72-2创11.02)130+2?50165.08(m)180180a50.72-R=(130+0.80)?sec130=14.75(m) 2215
2
E5=(R+p)sec
HZαLs