第1章 矩阵运算与矩阵分解_3(17)

矩阵论与数值分析

2

E A 1 1 3 1 1, 2 1, 3 3,

thus, A is diagonalizable.

For 1 1, sovle the equation E A x 0, 1 1 1 1 1 1 E A 2 2 4 0 0 2 , that is 1 1 3 0 0 0

x1 x2 x3 0 2 x3 0